如何在不损失宽高比的情况下使图像填充90％的屏幕

Question

Kindly view the snippet here https://jsfiddle.net/nc7edzck/

I want to display a image on click and it should fill screen irrespective of the screen size without distorting the aspect ratio.

.imgclick{
    position: fixed;
    top: 50%;left: 50%;
    transform: translate(-50%,-50%);
    z-index: 100001;
    max-height: 80%;
}

I tried everything but if it works on one screen it distorts for another screen of different screen size.

EDIT: Please try your solution by zooming in and out before posting. Also, we can throw the black strip out its not necessary. I can place it later independently.

 var ImageTrigger = false; $(document).on('click', '.image', function() { if (!ImageTrigger) { var ImgSrc = $("img", this); $("#imgFrame img").attr("src", ImgSrc.attr("src")); $("#imgFrame img").attr("alt", ImgSrc.attr("alt")); $("#imgFrame img").attr("title", ImgSrc.attr("alt")); $("#imgFrame .imgclicktext").html(ImgSrc.attr("alt")); $("#imgFrame").css('visibility', 'visible'); ImageTrigger = true; return false; } }); $(document).on('click', 'body', function() { if (ImageTrigger) { $("#imgFrame").css('visibility', 'hidden'); ImageTrigger = false; } }); 

 .imgclicktext { padding: 3px 15px; background-color: rgba(0, 0, 0, 0.6); color: white; text-align: center; margin-top: 15px; } img { /*transition: 0.3s ease-in-out;*/ max-width: 90%; max-height: 400px; /*! padding: 10px; */ } .imgclick { position: fixed; top: 50%; left: 50%; transform: translate(-50%, -50%); z-index: 100001; max-height: 80%; } #imgFrame { position: fixed; width: 100%; height: 100%; top: 0px; left: 0px; z-index: 100000; background-color: rgba(0, 0, 0, 0.5); visibility: hidden; min-width: 500px; } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div id="imgFrame"> <div class="imgclick"> <img style="margin: 0 auto;display: table;" src="" alt="" title="" class=""> <div class="imgclicktext" style=""></div> </div> </div> <div class="image" data-content="Not so sweet but ok!"> <img style="margin: 0px auto;display: table;" src="https://upload.wikimedia.org/wikipedia/commons/f/f5/Howlsnow.jpg" alt="Not so sweet but ok!" title="Hottie"> </div> 

Answer 1

Check out this fiddle https://jsfiddle.net/nc7edzck/4/

I added a window resize and changed a bit of css:

    var height = $('.image').height()*.9;
    var width = $('.image').width()*.9;

    $('#imgFrame img').css('height',height);
    $('#imgFrame img').css('width',width);

    $("#imgFrame").css('visibility', 'visible');

    $(window).resize(function(){
        height = $('.image').height()*.9;
        width = $('.image').width()*.9;
        $('#imgFrame img').css('height',height);
        $('#imgFrame img').css('width',width);
    });

Answer 2

Remove max-width: 90%; from the .img class and add the same into the .imgclick class. That should do the trick as we want to contain the container instead of the image inside.

[Edit]

Ignore this. Go with LegenJerry's answer with the resize. Its the best solution.

Was going through the css and trying to find a css trick to fix this came up with another solution. Hope this helps. Change the following in your fiddle:

img{
/*transition: 0.3s ease-in-out;*/
 max-width: 90%;
max-height: 90%;
/*! padding: 10px; */

}


.imgclick{
position: fixed;
top: 10%;left: 10%;
z-index: 100001;
max-height: 90%;

}