在同一脚本中执行两个查询

Question

I have made one script which is suppose to update 2 different table at the same time. The problem is that only one table get updated and I cant get why?

Logic is:

The script should update the record of job.status and customer.status at the same time after I click on update button.

Only the table job get updated.

I tried to run only the second query and does not work. I tried to run a query to another table on the same database but is not working.

Any suggestion?

here is my code:

     <?php
include("connection.php");

if (isset($_POST['update'])) {
  $results = $link->query("UPDATE job SET status='$_POST[status]', priority='$_POST[priority]' WHERE id='$_POST[hidden]'");
  $results = $link->query("UPDATE customer SET status='$_POST[status]' WHERE id='$_POST[hidden]'");
             }    
$sql = "SELECT * from job";
if (!$result = $link->query($sql)) {
    die('There was an error running the query [' . $link->error . ']');
}
echo "
<table class='table'>
    <thead>
        <tr>";
/* Get field information for all columns */
while ($finfo = $result->fetch_field()) {
    echo "  <th>" . $finfo->name . "</th>";  }
echo "
        </tr>  </thead> <tbody>";

while ($row = $result->fetch_assoc()) {
   $job_id = $row['id'];

    echo "<form action='' method=post>";
    echo "<tr class='info'>

                 <input type=hidden name=hidden value=" . $row['id'] . ">
                <td>" . $row['id'] . "</td> 
                <td>" . $row['device'] . "</td>
                  <td>" . $row['model'] . "</td> 
                <td>" . $row['problem'] . "</td>
            <td>

           <select class='form-control col-sm-10' id='status' name='status'>
                <option value='new' ". ($row['status'] == 'new'? 'selected ': '') .">New</option>
                <option value='progress' ". ($row['status'] == 'progress'? 'selected ': '') .">Progress</option>
                <option  value='wait' ". ($row['status'] == 'wait'? 'selected ': '') .">Wait</option>
                <option value='done' ". ($row['status'] == 'done'? 'selected ': '') .">Done</option>
                <option value='close' ". ($row['status'] == 'close'? 'selected ': '') .">Close</option>
            </select>
            </td>        

          <td> 
             <button type='submit' class='btn btn-primary btn-sm' name='update'>Update</button>
         </td>
          <td> 
                <a class='btn btn-primary btn-sm get_info'  data-toggle='modal' data-target='#myModal' name='job_id'  value= '[$job_id]'> Customer Info</a>              
             </form>                 
                </td>

           </tr>"; 
    echo "</form>";


}
echo "
    </tbody>

</table>";

?>

----UPDATE----

I notice that when i send this query is working.

$results = $link->query("UPDATE customer SET status='changethevalue' WHERE id='$_POST[hidden]'");

And when I send this one is working

 $results = $link->query("UPDATE customer SET status='changevalue'");

----UPDATE 2----

I rewrote the query like this and is apparently working. But I dont know why.

if (isset($_POST['update'])) {

  $results = $link->query("UPDATE customer SET status='$_POST[status]' WHERE id='$_POST[hidden]'");

  $results = $link->query("UPDATE job SET status='$_POST[status]' WHERE id='$_POST[hidden]'");

}

Answer 1

There is no issue in the update queries but make sure you are using corect column names or try echo the 2nd query and run in php myadmin f.ex.

echo $query="customer SET status='$_POST[status]' WHERE id='$_POST[hidden]'"

then

$results = $link->query($query);

Answer 2

The queries should work. Maybe your table customer is actually customers or the columns status or id are either named differently or have the wrong data type.

I would carefully copy/paste the second query directly into PhpMyAdmin or directly into your database and see whether it gives you any errors. Maybe it's trying to assign a blank status but nulls are not accepted?