从一台服务器向另一台服务器发送和收集数据

Question

UPDATE更新

Objective post data (age and name) from www.domain1.com to www.domain2.com/try.php从www.domain1.com到www.domain2.com/try.php客观发布数据（年龄和姓名）

Problem am getting this on domain2.com/try.php问题是在domain2.com/try.php上得到这个

Undefined index: name未定义索引：名称

Undefined index: age未定义索引：年龄

Index.html on domain1域 1 上的 Index.html

<html>
<head>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
    <script>
        $(document).ready(function () {
            $("#clickMe").click(function () {

                $.ajax({
                    type: 'post',
                    contentType: "application/json; charset=utf-8",
                    url: 'www.domain2.com/try.php',
                    dataType: "json",
                    data: {
                        name: "tom",
                        age: "30"
                    },
                    complete:
                            function (data) {
                                window.location = "www.domain2.com/try.php";
                            }
                })

            })
        })

    </script>
</head>
<body>
<input id="clickMe" type="button" value="clickme123"/>
</body>
</html>

try.php on domain2域2上的try.php

    <?php
$name = $_POST['name'];
$age = $_POST['age'];

echo 'name:'.$name;
echo 'age:'.$age;

Answer 1

On the first domain just use a form and post to the second domain:在第一个域上，只需使用表单并发布到第二个域：

<html>
    <head>
    </head>
    <body>
        <form action="http://two.example.com/foo.php" method="POST">
            <input type="hidden" name="name" value="tom">
            <input type="hidden" name="age" value="30">
            <input type="submit" value="Go">
        </form>
    </body>
</html>

从一台服务器向另一台服务器发送和收集数据

问题描述

1 个解决方案

解决方案1
1 已采纳 2016-10-26 12:16:17

从一台服务器向另一台服务器发送和收集数据

问题描述

1 个解决方案

解决方案1 1 已采纳 2016-10-26 12:16:17

解决方案1
1 已采纳 2016-10-26 12:16:17