[英]Disable 3D touch for UIButton in UITableViewCell
I have a UITableView
with customized UITableViewCells
. 我有一个UITableView
定制UITableViewCells
。 In the cells I have a UIButton
which I don't want to be trigged by the 3D touch event for the cell. 在单元格中,我有一个UIButton
,我不想被该单元格的3D触摸事件触发。
I want it to work in a similar manner as in Apples messages app , if you take a look there it works in the way that if you press the thumbnail for the message sender image (or initials) you get a different peek & pop from when you press the whole cell. 我希望它以与Apples消息应用程序中类似的方式工作,如果您在其中查看它的工作方式是,如果按消息发件人图像 (或首字母缩写)的缩略图 ,您将获得与众不同的窥视和弹出效果。您按下整个单元格。 Only difference is that I want to completely ignore the peek & pop for my button . 唯一的不同是, 我要完全忽略按钮的窥视和弹出 。 Anyone out there that knows a good solution to this? 有人知道对此有很好的解决方案吗?
Thank you in advance. 先感谢您。
Create a UIView
and use a UITapGestureRecognizer
with a custom force touch gesture recognizer like this DeepPressGestureRecognizer
. 创建一个UIView
并将UITapGestureRecognizer
与自定义的强制触摸手势识别器(如DeepPressGestureRecognizer
。 Set up the gesture recognizers in a way that the DeepPressGestureRecognizer
prevents the UITapGestureRecognizer
from recognizing. 以DeepPressGestureRecognizer
阻止UITapGestureRecognizer
识别的方式设置手势识别器。
I solved this by adding a UIButton
that covered the whole UITableViewCell
and then for the UIButton
I did not want to be triggered I created a separate UIView
with clear background that I laid on top of the 3D touch triggered UIButton
. 我通过添加一个覆盖整个UITableViewCell
的UIButton
来解决此问题,然后为不想被触发的UIButton
创建了一个单独的UIView
具有清晰的背景,并将其置于3D触摸触发的UIButton
之上。
This creates a 3D touch animation for the whole UITableViewCell
which looks awesomely beautiful. 这会为整个UITableViewCell
创建一个3D触摸动画,看起来非常漂亮。
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