使用RegEx从Java字符串中删除除-和_以外的所有标点符号

Question

I am trying to replace all punctuation except the - and _ using a method I found here, but I can only get it to work on " using the exact code as posted which used a negative lookahead:

(?!")\\p{punct}

//Java example:

String string = ".\"'";
System.out.println(string.replaceAll("(?!\")\\p{Punct}", ""));

I tried:

name = name.replaceAll("(?!_-)\\p{Punct}", ""); // which just replaces all punctuation.

name = name.replaceAll("(?!\_-)\\p{Punct}", ""); // which gives an error.

Thanks.

Answer 1

Use a character class subtraction (and add a + quantifier to match chunks of 1 or more punctuation chars):

name = name.replaceAll("[\\p{Punct}&&[^_-]]+", "");

See the Java demo .

The [\\\\p{Punct}&&[^_-]]+ means match any char from \\p{Punct} class except _ and - .

The construction you found can also be used, but you'd need to put the - and _ into a character class, and use .replaceAll("(?![_-])\\\\p{Punct}", "") , or .replaceAll("(?:(?![_-])\\\\p{Punct})+", "") .