[英]C/HTML: Correctly printing the username and password input of the user
I started experimenting with C/CGI/HTML a few days ago. 几天前,我开始尝试使用C / CGI / HTML。 I was piqued by some log-in page program that I saw so I tried to do my own: 我被看到的某些登录页面程序激怒了,所以我尝试自己做:
Here's my program: 这是我的程序:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(void)
{
char *data;
char *user;
char *password;
printf("Content-type:text/html\r\n\r\n");
printf("<!DOCTYPE html><html><head><title>Hello</title></head><body>");
data = getenv("QUERY_STRING");
if (data) {
sscanf(data,"user=%s&password=%s", user, password);
printf("Hello Mr./Ms. %s\n",user);
printf("You entered your password %s\n",password);
}
printf("<form action='http://localhost/10.html'>");
printf("<input type=text name=user>");
printf("<input type=password name =password>");
printf("</body></html>");
exit(EXIT_SUCCESS);
}
And whenever I execute my HTML file: 每当执行我的HTML文件时:
with an input of: 输入以下内容:
username = 123 password = 123 用户名= 123密码= 123
This is the output that this program gives me: 这是该程序给我的输出:
Hello Mr./Ms. 123&password=123 You entered your password (null)
Any idea how to fix this? 任何想法如何解决这个问题? Thanks! 谢谢!
In your piece of code 在你的代码中
char *user;
char *password;
user
and password
are just uninitialized pointers. user
和password
只是未初始化的指针。
You need this: 你需要这个:
char user[100];
char password[100];
But there are most likely other CGI and sscanf related problems. 但是,很可能还有其他CGI和sscanf相关的问题。
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