在console.log中运行一个直接的奇怪的行为错误

Question

I have code:

function fn(ob)
{
console.log(ob.name)
}

fn({name:"myName"})


(function(text){

console.log(text)

})("Error")

But when i run this i get TypeError: fn(...) is not a function [Learn More] on console. Why?

Answer 1

You need to separate between the call to the fn function and the definition (and call) to the anonymous function.
You can do this using the ; char after the call to the fn function:

 function fn(t) { console.log(t.name) } fn({name:"myName"}); (function(text){ console.log(text) })("Error") 

Otherwise your code is actually:

fn({name:"myName"})(function(text){
    console.log(text)
})("Error")

And this is the error you got.