[英]How to Convert Binary String to Byte-like Object in Python 3?
I have this line in my program: TextV = base64.b64decode('0cQ+bNsObaw=')
and the value of TextV
is b'\\xd1\\xc4>l\\xdb\\x0em\\xac'
. 我的程序中有以下代码行: TextV = base64.b64decode('0cQ+bNsObaw=')
, TextV
值为b'\\xd1\\xc4>l\\xdb\\x0em\\xac'
。 Then I run this to convert TextV to binary: 然后运行此命令将TextV转换为二进制文件:
TextVBin = ''.join(format(x, 'b') for x in bytearray(TextV))
and the value of TextVBin
is '11010001110001001111101101100110110111110110110110101100'
. 并且TextVBin
值为'11010001110001001111101101100110110111110110110110101100'
。 Now, I wanna again convert TextVBin format to TextV format(ie b'\\xd1\\xc4>l\\xdb\\x0em\\xac'
) But I googled and I couldn't find any answer. 现在,我想再次将TextVBin格式转换为TextV格式(即b'\\xd1\\xc4>l\\xdb\\x0em\\xac'
),但是我用b'\\xd1\\xc4>l\\xdb\\x0em\\xac'
搜索,但找不到任何答案。 How can I do this in Python 3? 如何在Python 3中做到这一点?
I would use: 我会用:
import struct
TextVBin = "{:b}".format(struct.unpack(">Q", TextV)[0])
to convert your TextV
to binary string. 将您的TextV
转换为二进制字符串。
It however produces 1101000111000100001111100110110011011011000011100110110110101100
which is different than your own output, but I guess that is because leading 0 are truncated for each byte with your own method. 但是,它会生成1101000111000100001111100110110011011011000011100110110110101100
,这与您自己的输出不同,但是我猜这是因为使用您自己的方法会为每个字节将前导0截断。 So your method is wrong. 所以你的方法是错误的。
using struct: 1101000111000100001111100110110011011011000011100110110110101100
使用结构: 1101000111000100001111100110110011011011000011100110110110101100
using yours: 1101000111000100 111110 110110011011011 1110 110110110101100
使用您的电话: 1101000111000100 111110 110110011011011 1110 110110110101100
Then to convert this binary string back to bytes: 然后将此二进制字符串转换回字节:
int('1101000111000100001111100110110011011011000011100110110110101100', 2).to_bytes(8, 'big')
Note: I assumed that your TextVBin is 8 bytes long and big endian based on your example. 注意:根据您的示例,我假设您的TextVBin长8字节,且字节序大。 If length is variable, my answer does not apply. 如果长度可变,我的答案将不适用。
The problem is that your format string truncates leading zeros. 问题是您的格式字符串会截断前导零。 You should use 你应该用
TextVBin = ''.join('{:08b}'.format(x) for x in bytearray(TextV))
which will format each byte with exactly 8 binary digits. 它将使用精确的8个二进制数字格式化每个字节。 Then, to reverse, simply do 然后,要扭转,只需做
TextV = bytearray([int(TextVBin[i:i+8], 2) for i in range(0, len(TextVBin), 8)])
For example: 例如:
>>> import base64
>>> TextV = base64.b64decode('0cQ+bNsObaw=')
>>> TextV
b'\xd1\xc4>l\xdb\x0em\xac'
>>> TextVBin = ''.join('{:08b}'.format(x) for x in bytearray(TextV))
>>> TextVBin
'1101000111000100001111100110110011011011000011100110110110101100'
>>> TextV = bytearray([int(TextVBin[i:i+8], 2) for i in range(0, len(TextVBin), 8)])
>>> TextV
bytearray(b'\xd1\xc4>l\xdb\x0em\xac')
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