[英]how to display data from database in html text boxes using php
i am displaying my table data in html page but i am getting blank page..... 我在html页中显示我的表格数据,但我正在空白页.....
i am new to php coding please help me..... 我是php编码的新手,请帮助我.....
this is my html code 这是我的HTML代码
<!DOCTYPE html>
<html>
<head>
<script>
function validate(){
var phonenumber=document.myform.phonenumber.value;
if(phonenumber.length>=10){
alert("Phonenumber must be at least 10 characters");
return false;
}
}
</script>
</head>
<body font-color="red">
<form name ="myform" action="dis.php" method="post" submit="return validate()">
<table border='0' width='480px' cellpadding='0' cellspacing='0' align='center'>
<center><tr>
<td><h1><marquee> Employee Details</marquee></h1></td>
</tr><center>
<table border='0' width='480px' cellpadding='0' cellspacing='0' align='center'>
<tr>
<td align='center'>Name:</td>
<td><input type='text' name='name' required></td>
</tr>
<tr> <td> </td> </tr>
<tr>
<td align='center'>id:</td>
<td><input type='text' name='id'></td>
</tr>
<tr> <td> </td> </tr>
<tr>
<td align='center'>roll number:</td>
<td><input type='text' name='rollnumber'></td>
</tr>
<tr> <td> </td> </tr>
<tr>
<td align='center'>Address:</td>
<td><input type='text' name='address'></td>
</tr>
<tr> <td> </td> </tr>
<tr>
<td align='center'>Phonenumber:</td>
<td><input type='text' name='phonenumber'></td>
</tr>
<tr> <td> </td> </tr>
<table border='0' cellpadding='0' cellspacing='0' width='480px' align='center'>
<tr>
<td align='center'><input type='submit' name='insert' value="insert"></td>
</tr>
<tr>
<td align='center'><input type='submit' name='update' value="update"></td>
</tr>
</table>
</table>
</table>
</form>
</body>
</html>
this is my php code 这是我的PHP代码
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<?php
$connection = mysql_connect('localhost', 'root','');
if (!$connection)
{
die("Database Connection Failed" . mysql_error());
}
$select_db = mysql_select_db( "emp",$connection);
if (!$select_db)
{
die("Database Selection Failed" . mysql_error());
}
else
{
session_start();
error_reporting(0);
$name = $_POST['name'];
$id = $_POST['id'];
$rollnumber = $_POST['rollnumber'];
$address = $_POST['address'];
$phonenumber = $_POST['phonenumber'];
if(isset($_POST['insert']))
{
$sql = mysql_query("SELECT * FROM venu ");
$result = mysql_query($sql) or die(mysql_error());
$n=mysql_num_rows($result);
if($n > 0)
{
echo "<table>";
echo "<th>name</th>";
echo "<th>id</th>";
echo "<th>rollnumber</th>";
echo "<th>address</th>";
echo "<th>phonenumber</th>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['rollnumber'] . "</td>";
echo "<td>" . $row['address'] . "</td>";
echo "<td>" . $row['phonenumber'] . "</td>";
echo "</tr>";
}
echo "</table>";
}
else
{
echo "No records matching your query were found.";
}
}
else
{
echo "ERROR: Could not able to execute.";
}
}
mysql_close($connection);
?>
</body>
</html>
i am getting error only blank page displaying... please help me.... 我收到的错误仅显示空白页...请帮助我...
You are using mysql_query()
twice. 您两次使用mysql_query()
。 Change this: 更改此:
$sql = mysql_query("SELECT * FROM venu ");
$result = mysql_query($sql) or die(mysql_error());
Into: 进入:
$sql = "SELECT * FROM venu ";
$result = mysql_query($sql) or die(mysql_error());
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.