如何将Promise.all（）。then返回到函数

Question

I am trying to return a Promise.all() to a function. I tried different ways but it is showing errors

here is my code

// All this iam doing in my server side controller
Promise = require('bluebird');

function countByTitle(accrdnArray) {
  console.log(accrdnArray) // array of objects is printing here
  var arrayCount = countfunc(accrdnArray);
  console.log(JSON.stringify(arrayCount)) // here it is not printing showing error 
}

function countfunc(accrdnArray) {
  var array = [];
  for (var i = 0; i < accrdnArray.lenght; i++) {
    var heading = accrdnArray[i].name;
    array.push(mongoCount(heading));
  }

  return Promise.all(array).then(resultantCount => {
      console.log(JSON.stringify(resultantCount)); // resultanCout printing here
      return resultantCount
    })
    // Here i want to return the resultantCount to above function.        
}

function mongoCount(heading) {
  var mongoQuery = {
    "ProCategory.title": heading
  }
  return Collection.count(mongoQuery).then(function(count) {
    return {
      name: categoryTitle,
      count: count
    };
  });
}

Answer 1

return Promise.all(array).then(resultantCount =>{
    console.log(JSON.stringify(resultantCount )); // resultanCout printing here
    return resultantCount;
});

This part of the code returns a Promise object. So you have to use .then() again in your countByTitle function.

function countByTitle(accrdnArray) {
  console.log(accrdnArray) // array of objects is printing here
  var arrayCount = countfunc(accrdnArray);
  arrayCount.then(function(count) {
    console.log(JSON.stringify(count));
  });
}