可观察的超时

Question

Assume that I have following.

Observable.range(1,1000)
.flatMap(i -> Observable.just(i)
    .subscribeOn(Schedulers.computation()
    .map(i2 -> calculate(i2))
).subscribe(System.out::println)

In here I have an observable from 1 to 1000 and each number is mapped using calculate()(a large mehod) in different threads.I need to set a timeout until some amount of items returned.

Say I have a timeout of 2 seconds.

I need 2-50 items to be subscribed.(At least 2 items should be subscribed but not more than 50 items)

If 2 items do not emitted within 2 seconds restart timeout.

Say 10 items returned within timeout.Then no problem execute the rest of the code.

How can I do this using Rx Java?

Answer 1

这可以使用rx-java中的buffer（）而不是使用timeout（）来实现