验证，我在做什么错？

Question

So basiclly i just want this code below:

    //basic email validation
    if(!eregi('^x[\d]{8}@student\.ncirl\.ie$', $email)){
        // Return Error - Invalid Email
        $error = true;
        $emailError = 'The email you have entered is invalid, please try again.';
    }
    if ( !filter_var($email,FILTER_VALIDATE_EMAIL) ) {
        $error = true;
        $emailError = "Please enter valid email address.";
    } else {
        // check email exist or not
        $query = "SELECT userEmail FROM users WHERE userEmail='$email'";
        $result = mysql_query($query);
        $count = mysql_num_rows($result);
        if($count!=0){
            $error = true;
            $emailError = "Provided Email is already in use.";
        }
    }

To validate the email if it is exactly similar to email - "x14332684@student.ncirl.ie" , i want it to keep the x at the start, have 8 random numbers after x and as it is everything after @. Only numbers to be random and the rest should be a "must". I just cant get it to validate the email like i want, using this code tells me pernament "The email you have entered is invalid, please try again.". Can anyone edit the code for me and point out what am i doing wrong in it? Thank you.

Answer 1

This works with preg_match. One thing you need to do is wrap the pattern with delimiters, most use / like:

if(!preg_match('/^x[\d]{8}@student\.ncirl\.ie$/', $email)){
    // Return Error - Invalid Email
    $error = true;
    $emailError = 'The email you have entered is invalid, please try again.';
}

http://php.net/manual/en/function.preg-match.php

Answer 2

使用此站点： http : //www.phpliveregex.com/以获取将来的preg_matche