在一个html表中显示多个数组

Question

I'm trying to display multiple arrays into a table so that each value is on a separate line within the table.

This is my current setup:

<?php

$id = $_GET['id'];

$result = mysqli_query($mysqli, "SELECT * FROM invoices WHERE id=$id");

while($res = mysqli_fetch_array($result))
{
?>

 <tr>
   <td><? echo $res['partnumber']; ?></td>
   <td><? echo $res['partdescription']; ?></td>
   <td><? echo $res['partprice']; ?></td>
   <td><? echo $res['partquantity']; ?></td>

<?php
    }

?>

Which displays the following:

Screenshot

instead i need it to display each value on a separate line

I tried the following but it duplicates its value over and over again.

<? foreach ($res as $row) : ?>
 <tr>
   <td><? echo $row['partnumber']; ?></td>
   <td><? echo $row['partdescription']; ?></td>
   <td><? echo $row['partprice']; ?></td>
   <td><? echo $row['partquantity']; ?></td>
 </tr>
 <? endforeach; 
 }
 ?>

Answer 1

First of all, your code is vulnerable to SQL injection, make sure to secure $id (ex. $id = (int)$_GET['id']; ) before putting it into your query string.

then try:

while($res = mysqli_fetch_array($result))
{
?>
 <tr>
   <td><? echo $res['partnumber']; ?></td>
 </tr><tr>
   <td><? echo $res['partdescription']; ?></td>
 </tr><tr>
   <td><? echo $res['partprice']; ?></td>
 </tr><tr>
   <td><? echo $res['partquantity']; ?></td>
 </tr>
<?php
    }

?>

Answer 2

If you need new line for each column must simply add new tr for each td

Try this:

<? foreach ($res as $row) : ?>
    <tr>
      <td><? echo $row['partnumber']; ?></td>
    </tr>
    <tr>
      <td><? echo $row['partdescription']; ?></td>
    </tr>
    <tr>
      <td><? echo $row['partprice']; ?></td>
    </tr>
    <tr>
      <td><? echo $row['partquantity']; ?></td>
    </tr>
 <? endforeach; ?>

Answer 3

Notice the change in the starting curly braces, and that i removed the endforeach you used, and the table tags...

Now you can make use of this in your for each loop.

 <table>
 <? foreach ($res as $row) { ?>
    <tr>
    <td><? echo $row['partnumber']; ?></td>
    <td><? echo $row['partdescription']; ?></td>
    <td><? echo $row['partprice']; ?></td>
    <td><? echo $row['partquantity']; ?></td>
    </tr>
 <? 
     }
 ?>
 </table>

I think this should do the trick

Answer 4

This is what i'm getting with your code: (i'll fix the security issue after i get this working, thank you)

    <?php

    $id = $_GET['id'];


    $result = mysqli_query($mysqli, "SELECT * FROM invoices WHERE id=$id");

    while($res = mysqli_fetch_array($result))
    {
    ?>
    <? foreach ($res as $row) { ?>
<tr>
<td><? echo $row['partnumber']; ?></td>
<td><? echo $row['partdescription']; ?></td>
<td><? echo $row['partprice']; ?></td>
<td><? echo $row['partquantity']; ?></td>
</tr>
    <? 
    }

    }

    ?>

Answer 5

 $arr1 = ['name'=>'jon', 'age'=>30, 'address'=>'dilly']; $arr2 = ['name'=>'gita', 'age'=>20, 'address'=>'goha']; $arr3 = ['name'=>'sita', 'age'=>20, 'address'=>'pune']; $agroup = array([$arr1, $arr2, $arr3]); ?> <table> <?php foreach($agroup as list($a, $b, $c)){ ?> <tr> <td><?php echo $a['name']; ?></td> <td><?php echo $b['name']; ?></td> <td><?php echo $c['name']; ?></td> </tr> <tr> <td><?php echo $a['age']; ?></td> <td><?php echo $b['age']; ?></td> <td><?php echo $c['age']; ?></td> </tr> <tr> <td><?php echo $a['address']; ?></td> <td><?php echo $b['address']; ?></td> <td><?php echo $c['address']; ?></td> </tr> <?php } ?> </table>