查找从EXE包装程序启动的Powershell脚本的完整路径

Question

I am trying to create an .exe file that is a packaged powershell script (script.ps1) in which part of the script is to print the current location of the .exe file NOT the Script.

Part of the Requirement is that the .exe needs to be portable:

So when I run File.exe or Double-click File.exe:

If the location of the file is C:\\Hello\\File.exe , it should print "C:\\Hello\\"

If the location is moved to D:\\Goodbye\\File.exe , it should print "D:\\Goodbye\\"

If the the file is COPIED to D:\\HELLO\\File.exe , it should ONLY print "D:\\HELLO\\"

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I have tried $PSScriptRoot but that only links to a temp folder

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What code can I add to the script.ps1 before packaging it as an .exe to make it look for the specific location of the .exe file?

Thanks

Answer 1

The tool you're using to wrap your PowerShell script in an *.exe , Ps1 to Exe , does the following when the *.exe is invoked:

• It extracts the embedded script to a temporary file in subtree $env:TEMP .

• It invokes the PowerShell executable , and passes it the path to the temporary script file via -File , along with -ExecutionPolicy Bypass .

Example command line invoked by a wrapper *.exe :

"powershell" -ExecutionPolicy Bypass -File C:\Users\jdoe\AppData\Local\Temp\2409.tmp\240A.ps1

You therefore need to examine the parent process of the PowerShell instance running your script in order to obtain information about the wrapper *.exe .

# Get the parent process.
# (`gps` is a built-in alias of `Get-Process`)
$pp = gps -Id (Get-CimInstance win32_process -Filter "ProcessId = $PID").ParentProcessId

# Output the parent process executable's directory path:
Split-Path $pp.Path

Note: If you're still on PSv2, use Get-WmiObject instead of Get-CimInstance .

Answer 2

I've never worked with packaged PowerShell scripts, but if the PowerShell engine is being hosted by the EXE packaging the script, then something like this should do the trick:

$FullPathToEXE = [System.Diagnostics.Process]::GetCurrentProcess().MainModule.FileName

$DirectoryContainingEXE = [System.IO.Path]::GetDirectoryName($FullPathToEXE)