订阅两个不同的Observable和onNext两者？

Question

Given I subscribe to 2 different Observables and I want get both of them on onNext after do some operations to them

let's say I have 2 Observables

Observable<List<String>> childName = Observable.from(children)... some operations
Observable<List<String>> teacherName = Observable.from(teachers)... some operations

how do I get both of them on my subscribe?

subscribe( 
    onNext(List<String> childName, List<String> className)

so that I can pass both of them in my listener in that manner.

I don't want to combine them, I just want when after the operations are finished, get both of them and pass it on my subscriptions

Answer 1

You can zip their values into a Pair :

Observable.zip(childName, className, 
    (a, b) -> Pair.of(a, b))
.subscribe((Pair<List<String>, List<String>> pair) -> {
    // do something with pair.first and pair.second
}, Throwable::printStackTrace);

Answer 2

hacky but simple

Observable.zip(childName, teacherName, (childList, teachersList) -> {
    // handle childList & teachersList
    return Observable.empty();
}).subscribe(o -> {}, error -> {
    //handle errors
});