Neo4j：如何从路径中的节点获取其他节点？

Question

I have nodes in a chain, like this:

(n {height:100})
 |
(n)
 |
(n)
 |
(n)
 |
(n)

I can get these nodes with this cypher query:

MATCH chain=(start :n {height:100})-[:chain*4]->(end :n)
RETURN chain

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However, each node in this chain also has a single node coming off it with a specific relationship, like this:

(n)-[:single]->(o)
 |
(n)-[:single]->(o)
 |
(n)-[:single]->(o)
 |
(n)-[:single]->(o)
 |
(n)-[:single]->(o)

I would like to return each (n) , as well as the (o) coming off it.

Is it possible to do this in one cypher query?

Answer 1

Shouldn't be a problem, though this is easier if we don't match on the path, but get all nodes in the chain (and the single node off of each) instead.

MATCH (start :n {height:100})-[rels:chain*0..4]->(chainlink :n)-[:single]->(o)
RETURN chainlink, o
ORDER BY SIZE(rels)

Answer 2

Okay, it seems the use of WITH(chain) and UNWIND does the trick:

MATCH chain=(start :n {height:100})-[:chain*4]->(end :n)
WITH NODES(chain) AS nodes
UNWIND nodes as node
OPTIONAL MATCH (node)-[:single]->(o :o)
RETURN nodes, COLLECT(o) as os