二进制到 Python 中的字符串/文本

Question

I have searched many times online and I have not been able to find a way to convert my binary string variable, X

X = "1000100100010110001101000001101010110011001010100"

into a UTF-8 string value.

I have found that some people are using methods such as

b'message'.decode('utf-8')

however, this method has not worked for me, as 'b' is said to be nonexistent, and I am not sure how to replace the 'message' with a variable. Not only, but I have not been able to comprehend how this method works. Is there a better alternative?

So how could I convert a binary string into a text string?

EDIT: I also do not mind ASCII decoding

CLARIFICATION: Here is specifically what I would like to happen.

def binaryToText(z):
    # Some code to convert binary to text
    return (something here);
X="0110100001101001"
print binaryToText(X)

This would then yield the string...

hi

Answer 1

It looks like you are trying to decode ASCII characters from a binary string representation (bit string) of each character.

You can take each block of eight characters (a byte), convert that to an integer, and then convert that to a character with chr() :

>>> X = "0110100001101001"
>>> print(chr(int(X[:8], 2)))
h
>>> print(chr(int(X[8:], 2)))
i

Assuming that the values encoded in the string are ASCII this will give you the characters. You can generalise it like this:

def decode_binary_string(s):
    return ''.join(chr(int(s[i*8:i*8+8],2)) for i in range(len(s)//8))

>>> decode_binary_string(X)
hi

If you want to keep it in the original encoding you don't need to decode any further. Usually you would convert the incoming string into a Python unicode string and that can be done like this (Python 2):

def decode_binary_string(s, encoding='UTF-8'):
    byte_string = ''.join(chr(int(s[i*8:i*8+8],2)) for i in range(len(s)//8))
    return byte_string.decode(encoding)

Answer 2

Provide the optional base argument to int to convert:

>> x = "1000100100010110001101000001101010110011001010100"
>> int(x, 2)
301456912901716

Answer 3

In Python 2, an ascii-encoded (byte) string is also a utf8-encoded (byte) string. In Python 3, a (unicode) string must be encoded to utf8-encoded bytes. The decoding example was going the wrong way.

>>> X = "1000100100010110001101000001101010110011001010100"
>>> X.encode()
b'1000100100010110001101000001101010110011001010100'

Strings containing only the digits '0' and '1' are a special case and the same rules apply.

Answer 4

To convert bits given as a "01"-string (binary digits) into the corresponding text in Python 3:

>>> bits = "0110100001101001"
>>> n = int(bits, 2)
>>> n.to_bytes((n.bit_length() + 7) // 8, 'big').decode()
'hi'

For Python 2/3 solution, see Convert binary to ASCII and vice versa .

Answer 5

A working code for python 3

Binstr = '00011001 00001000'
Binstr.split(' ')
s = []
for i in Binstr:
    s.append(chr(i))
print(''.join(s))