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MongoDB $ concatenate日期错误

[英]MongoDB $concatenate Date Error

I am working on a mongo aggregation project to group average readings every two hours which returns the desired output as follows 我正在进行一个mongo汇总项目,以便每两个小时对平均读数进行分组,以返回所需的输出,如下所示

{
        "_id": {
            "Year": 2016,
            "locationID": " WL 001",
            "Day": 25,
            "Hour": 12,
            "Month": 1
        },
        "temperature": 10.858749999999999,
        "pH": 0,
        "Conductivity": 2032.375
    }

I want to regroup the data format and concatenate the date portion of the _id field so that it represent a new data format format below 我想重新组合数据格式并连接_id字段的日期部分,以便它代表下面的新数据格式

{
    "_id": {
       "locationID": " WL 001",
    },
    "Readings": {
        "temperatue": {
            "value": 8.879
        },
        "SensoreDate": {
            "value": "2016-01-25:12"
        },
        "pH": {
            "value": 16.81
        },
        "Conductivity": {
            "value": 1084
        }
    },
}

Here is the $project portion of my aggregation query 这是我的聚合查询的$ project部分

{
    "$project": {
        '_id': '$_id.locationID',
        'Readings': {
            'pH': {'value': '$pH'},
            'temperature': {'value': '$temperature'},
            'Conductivity': {'value': '$Conductivity'},
            'SensoreDate': {'value': {'$concat': ["$_id.Year", "$_id.Month", "$_id.Day", "$_id.Hour"]} }
        }
    }
}

but i am getting an error $concat only supports strings, not NumberInt32 I have tried several options but can not get it to work 但我遇到一个错误$ concat仅支持字符串,不支持NumberInt32我尝试了几种方法但无法正常工作

Conversion of int to str will not be possible in the pipeline. 在管道中无法将int转换为str。 So $concat wont be possible on for the given data format. 因此,对于给定的数据格式, $concat是不可能的。

Another method which could work would be trick to convert the year, month, day into a BSON Date format object. 另一种可行的方法是将年,月,日转换为BSON Date格式对象的技巧

The inspiration is that dateObj: {$add: [new Date(0), '$time_in_sec_epoch']} . 灵感来自dateObj: {$add: [new Date(0), '$time_in_sec_epoch']}

The calculation of $time_in_sec_epoch can be done using aggregation operators like $sum , $divide , $subtract etc. You can use the formula as given in this answer . $time_in_sec_epoch的计算可以使用聚合运算符(例如$sum$divide$subtract等)完成。您可以使用此答案中给出的公式。 This will be tedious, but hopefully you get the idea. 这将很乏味,但希望您能理解。

For the dateObj to a string part use $dateToString 对于dateObj到字符串部分,请使用$dateToString

You may use concat with substr to join them into a date. 您可以将concat与substr一起使用,以将它们加入日期中。

'SensoreDate': {
    'value': {
        '$concat': [{
                $substr: ["$_id.Year", 0, -1]
            },
            "-", {
                $substr: ["$_id.Month", 0, -1]
            },
            "-", {
                $substr: ["$_id.Day", 0, -1]
            },
            ":", {
                $substr: ["$_id.Hour", 0, -1]
            }
        ]
    }
 }

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