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序言:查找偶数将它们添加到列表中

[英]Prolog: Find even numbers add them on a list

Write predicate evenNumbers(L1, L2) which is true if the list L1 containing random integers and the list L2 contains even integers from L1 . 编写谓词evenNumbers(L1, L2) ,如果列表L1包含随机整数,列表L2包含来自L1偶数整数,则为true。

For example: 例如:

?-evenNumbers ([2,1,-3,6,8,9], L2). 

»Your program returns L2 = [2,6,8]. »您的程序返回L2 = [2,6,8].

My code is: 我的代码是:

    evenNumbers([],[]).
    evenNumbers([H|T],L):-
        integer(H),
        0 is H mod 2,
        append([H],L,L);
        evenNumbers(T,L).

Your code has multiple issues append([H],L,L); 您的代码有多个问题append([H],L,L); will stop recursion and give you a wrong list also your if-then-else statement isn't right .So you could write: 将会停止递归并给您一个错误的列表,如果您的if-then-else语句也不正确,那么您可以这样写:

 evenNumbers([],[]).
 evenNumbers([H|T],L1):-
        integer(H),
        (H mod 2 =:=0 -> L1=[H|T1],evenNumbers(T,T1);
        evenNumbers(T,L1) ).

Example: 例:

?- evenNumbers([2,1,-3,6,8,9], L2).
L2 = [2, 6, 8].

Another way writing it would be: 编写它的另一种方式是:

evenNumbers(L1,L2):-findall(X,(member(X,L1), X mod 2=:=0),L2).

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