[英]PHP/MYSQL display mysql record age using datediff
I'm new to PHP/MYSQL, I'm trying to display the age of all records from my database using DATEIFF
as shown in the line 17 of my code, but it just won't work. 我是PHP / MYSQL的新手,我正在尝试使用DATEIFF
显示数据库中所有记录的使用DATEIFF
,如代码的第17行所示,但这是行不通的。 I need somebody to help me out with this. 我需要有人帮我解决这个问题。
$result = mysqli_query($con,"SELECT * FROM growers");
echo "<table class='table table-striped table-advance table-hover'>
<tbody>
<tr>
<th><i class='icon_profile'></i> Batch</th>
<th><i class='icon_ol'></i> Date Received</th>
<th><i class='icon_clock_alt'></i> Age when Received</th>
<th><i class='icon_clock_alt'></i> Current Age</th>
<th><i class='icon_star'></i> NO of Birds</th>
<th><i class='icon_info'></i> View More</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo"<tr>";
echo"<td>" . $row['BATCH'] . "</td>";
echo"<td>" . $row['BIRTH DAY'] . "</td>";
echo"<td>" . $row['AGE'] . " Week(s)" . "</td>";
echo"<td>" . "SELECT DATEDIFF("NOW()", "$row['BIRTH DAY']") AS CURRENT AGE". "</td>";
echo"<td>" . $row['NO OF BIRDS'] . "</td>";
echo"<td>" . $row['AGE'] . "</td>";
echo"</tr>";
}
echo "</table>";
mysqli_close($con);
?>
You could select in main select 您可以在主选择中选择
$result = mysqli_query($con,
"SELECT
growers.BATCH,
growers.`BIRTH DAY`,
growers.AGE,
DATEDIFF(NOW(),growers.`BIRTH DAY`) AS CURRENT_AGE,
growers.`NO OF BIRDS`
FROM growers; "
);
echo "<table class='table table-striped table-advance table-hover'>
<tbody>
<tr>
<th><i class='icon_profile'></i> Batch</th>
<th><i class='icon_ol'></i> Date Received</th>
<th><i class='icon_clock_alt'></i> Age when Received</th>
<th><i class='icon_clock_alt'></i> Current Age</th>
<th><i class='icon_star'></i> NO of Birds</th>
<th><i class='icon_info'></i> View More</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo"<tr>";
echo"<td>" . $row['BATCH'] . "</td>";
echo"<td>" . $row['BIRTH DAY'] . "</td>";
echo"<td>" . $row['AGE'] . " Week(s)" . "</td>";
echo"<td>" . $row['CURRENT_AGE'] . "</td>";
echo"<td>" . $row['NO OF BIRDS'] . "</td>";
echo"<td>" . $row['AGE'] . "</td>";
echo"</tr>";
}
echo "</table>";
mysqli_close($con);
?>
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.