使用psutil杀死每个python进程名称，除了一个

Question

I'm using the following python script to kill every process with the given name:

import psutil

for proc in psutil.process_iter():
    if proc.name() == "processname":
        proc.kill()

I want the script to leave one process with the given name open. How can I achieve this? Is it possibile using this method?

Answer 1

You should simply skip the first one:

piter = psutil.process_iter()
first = True
for proc in psutil.process_iter():
    if proc.name() == "processname":
        if First:
            First = False
        else:
            proc.kill()

Answer 2

这是另一个可行的解决方案：

[func() for func in [proc.kill for proc in psutil.process_iter() if proc.name()=="processname"][1:]]