简体   繁体   English

将(来回)UNIX 时间戳转换为系列的 pandas.tslib.Timestamp 和 datetime

[英]Convert (back and forth) UNIX timestamp to pandas.tslib.Timestamp and datetime for series

I am working with python 3.5.2, pandas 0.18.1 and sqlite3.我正在使用 python 3.5.2、pandas 0.18.1 和 sqlite3。

In my data base, I have a column unix_time with INT for seconds since 1970. Ideally I want to read my dataframe from sqlite, and then create a time column which would correspond to the datetime or pandas.tslib.Timestamp conversion of the unix_time column that I woul only use for some processing and then drop before saving the dataframe back.在我的数据库中,我有一列unix_timeINT自 1970 年以来的秒数。理想情况下,我想从 sqlite 读取我的数据帧,然后创建一个time列,它对应于unix_time列的datetimepandas.tslib.Timestamp转换我只会用于一些处理,然后在保存数据帧之前删除。

The issue is that when parsing the unix_time column using :问题是在解析unix_time列时使用:

df = pd.read_from_sql_query("SELECT * FROM test", con, parse_dates=['unix_time'])

I obtain pandas.tslib.Timestamp types which is fine for my processing, but then I have to recreate my original unix_time column using :我获得了适合我的处理的pandas.tslib.Timestamp类型,但随后我必须使用以下方法重新创建我的原始unix_time列:

df['unix_time'][i] = (df['unix_time'][i] - datetime(1970,1,1)).total_seconds()

which is really 'dirty'这真的很“脏”

First question : Do you have a better way?第一个问题:你有更好的方法吗?

I thought about giving up the unix time format and only use datetime format but the to_datetime method from pandas returns in fact pandas.tslib.Timestamp ... And anyway, doing so would force me to iterate over all rows which is a bad solution.我想放弃 unix 时间格式,只使用datetime格式,但是 pandas 的to_datetime方法实际上返回了pandas.tslib.Timestamp ......无论如何,这样做会迫使我遍历所有行,这是一个糟糕的解决方案。 (It is impossible to apply to_datetime on something else than a view over a single cell of the dataframe (除了数据帧的单个单元格上的视图to_datetime ,不可能将to_datetime应用于其他内容

Second question : Is it possible to apply it on a series?第二个问题:是否可以将其应用于系列?

My last try was with directly using df['time'] = datetime.datetime.fromtimestamp(df['unix_time']) but surprisingly, it also returns pandas.tslib.Timestamp .我的最后一次尝试是直接使用df['time'] = datetime.datetime.fromtimestamp(df['unix_time'])但令人惊讶的是,它也返回pandas.tslib.Timestamp

In the end, knowing that I can only save unix timestamps or datetimes, my only choices for the moment are :最后,知道我只能保存 unix 时间戳或日期时间,我目前唯一的选择是:

  • parsing but then having to convert them back to unix timestamp one by one.解析但随后必须将它们一一转换回 unix 时间戳。

  • Or not parse it but have to convert them to pandas.tslib.Timestamp one by one.或者不解析它而是必须将它们pandas.tslib.Timestamp转换为pandas.tslib.Timestamp

It would be great if I could convert a whole series.如果我可以转换整个系列,那就太好了。

Last question : Is there a way to convert a unix timestamps series to datetime (or at least pandas.tslib.Timestamp ), or a pandas.tslib.Timestamp (or datetime ) series to unix timestamps?最后一个问题:有没有办法将 unix 时间戳系列转换为datetime (或至少pandas.tslib.Timestamp ),或将pandas.tslib.Timestamp (或datetime )系列转换为 unix 时间戳?

Thanks谢谢

EDIT: During my processing, I extract a row that I want to append to my dataset.编辑:在处理过程中,我提取了要附加到数据集的行。 Apparently, the coversion to pandas.tslib.Timestamp appends implicitly when passing from dataframe to serie :显然,当从数据帧传递到 serie 时,对 pandas.tslib.Timestamp 的pandas.tslib.Timestamp隐式附加:

df = pd.DataFrame({'UNX':pd.date_range('2016-01-01', freq='9999S', periods=10).astype(np.int64)//10**9})
df['Date'] = pd.to_datetime(df.UNX, unit='s')
print(df.Date.dtypes)
print(type(df['Date'][0]))
test = df.iloc[0]
print(type(test.Date))
new_df = test.to_frame().transpose()   #from here, impossible to do : new_df.to_sql("test", con) because the type for 'Date' is not supported
print(new_df.Date.dtypes)

returns返回

datetime64[ns]
<class 'pandas.tslib.Timestamp'>
<class 'pandas.tslib.Timestamp'>
object

Is there a way to convert the 'Date' in new_df from pandas.tslib.Timestamp to datetime64[ns] or datetime.datetime (or simply str ) ?有没有办法将new_df的“日期”从pandas.tslib.Timestampdatetime64[ns]datetime.datetime (或只是str )?

IIUC you can do it this way: IIUC 你可以这样做:

In [96]: df = pd.DataFrame({'UNX':pd.date_range('2016-01-01', freq='9999S', periods=10).astype(np.int64)//10**9})

In [97]: df
Out[97]:
          UNX
0  1451606400
1  1451616399
2  1451626398
3  1451636397
4  1451646396
5  1451656395
6  1451666394
7  1451676393
8  1451686392
9  1451696391

Convert UNIX epoch to Python datetime:将 UNIX 纪元转换为 Python 日期时间:

In [98]: df['Date'] = pd.to_datetime(df.UNX, unit='s')

In [99]: df
Out[99]:
          UNX                Date
0  1451606400 2016-01-01 00:00:00
1  1451616399 2016-01-01 02:46:39
2  1451626398 2016-01-01 05:33:18
3  1451636397 2016-01-01 08:19:57
4  1451646396 2016-01-01 11:06:36
5  1451656395 2016-01-01 13:53:15
6  1451666394 2016-01-01 16:39:54
7  1451676393 2016-01-01 19:26:33
8  1451686392 2016-01-01 22:13:12
9  1451696391 2016-01-02 00:59:51

Convert datetime to UNIX epoch:datetime时间转换为 UNIX 纪元:

In [100]: df['UNX2'] = df.Date.astype('int64')//10**9

In [101]: df
Out[101]:
          UNX                Date        UNX2
0  1451606400 2016-01-01 00:00:00  1451606400
1  1451616399 2016-01-01 02:46:39  1451616399
2  1451626398 2016-01-01 05:33:18  1451626398
3  1451636397 2016-01-01 08:19:57  1451636397
4  1451646396 2016-01-01 11:06:36  1451646396
5  1451656395 2016-01-01 13:53:15  1451656395
6  1451666394 2016-01-01 16:39:54  1451666394
7  1451676393 2016-01-01 19:26:33  1451676393
8  1451686392 2016-01-01 22:13:12  1451686392
9  1451696391 2016-01-02 00:59:51  1451696391

Check:检查:

In [102]: df.UNX.eq(df.UNX2).all()
Out[102]: True

Round trip between Pandas Timestamp and Unix Seconds (since 1970-01-01): Pandas Timestamp 和 Unix Seconds 之间的往返(自 1970-01-01):

date_in = pd.to_datetime("2022-04-07")
# type(date_in) is: pandas._libs.tslibs.timestamps.Timestamp
unix_seconds = date_in.value//10**9
date_out = pd.to_datetime(unix_seconds, unit="s")

Output:输出:

date_in
Out[1]: Timestamp('2021-04-07 00:00:00')
unix_seconds
Out[2]: 1617753600
date_out
Out[3]: Timestamp('2021-04-07 00:00:00')

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM