D3.js节点颜色基于类型

Question

Given the below json structure:

{
    "nodes": [
        {
        "type": "school",
        "country": "US",
        "name": "saint peter's",
        "id": 1006
        },
        {
        "type": "univeristy",
        "country": "Brazil",
        "name": "saint joseph's",
        "id": 1007
        }        
        ...
    ],
    "links": [
            {
            "source": 1006,
            "target": 1007,
            "value": 20            
        },

    ],
    "types": [
                {
                    "type": "school",
                    "image": "image01"
                },
                {
                    "type": "univeristy",
                    "image": "image02"
                },
                {
                    "type": "company",
                    "image": "image03"
                },
            ]   
}

I get the list of the type of nodes from types.type and append it to a html tag; assigning a color to each list item. When I change the color in the color picker container, in any of the list items, it only changes the color for .school , because it is hardcoded in here MyNode = d3.select("#node").selectAll(".school").select("circle"); how can I change it to match the type in the list item with the node type found in the nodes.type ?

$(document).ready(function () {
    $.getJSON("data.json", function (obj) {
        $('#filterColor').data('types', obj.types.map(function (o) {
            // console.log(o.type);
            return o.type;
        })).append(obj.types.map(function (o) {
            return '<li>' + o.type + '<input class="color-picker" type="text"/></li>';
        }).join(''));

        $("#filterColor .color-picker").each(function(){
            $(this).spectrum({
                color: (function (m, s, c) {
                    return (c ? arguments.callee(m, s, c - 1) : '#') +
                        s[m.floor(m.random() * s.length)]
                })(Math, '0123456789ABCDEF', 5),
                preferredFormat: "rgb",
                showInput: true,
                showPalette: true,
                showAlpha: true,
                palette: [["red", "rgba(0, 255, 0, .5)", "rgb(0, 0, 255)"]],
                change: function(color) {
                    MyNode = d3.select("#node").selectAll(".school").select("circle");
                    MyNode.style("fill", function(d) { return d3.rgb(color.toHexString()) });
                    ColorSchool = d3.rgb(color.toHexString());
                }
            });
        });
    });
});

which passes into this function:

function ColorType(d)
{
  if (d.type == "school") { return ColorSchool;}
  if (d.type == "univeristy"){ return Coloruniveristy;}
  if (d.type == "company"){ return Colorcompany;}
}

Answer 1

You could store the type reference in the actual element, in a custom attribute. Since it's only one string you need, this might be enough to fix your problem.

When creating the <li> element, you add an attribute, eg: data-fortype , with the o.type string.

In the each that initializes the spectrum thingy, you extract it using this.getAttribute or the jQuery equivalent.

An example, in vanilla js: (I don't really know the jQuery API, sorry about that)

 var data = { "types": [{ "type": "school", "image": "image01" }, { "type": "univeristy", "image": "image02" }, { "type": "company", "image": "image03" }] }; // Make UI from code: makeUI(); function makeLi(type) { return "<li>" + type.type + // (1) Here, the selector is stored in attr. "<input class='test' data-forType='" + type.type + "' type='text' /></li>" }; function onChange(e) { // (2) Here, we retreive the attribute console.log("Selector: " + e.target.getAttribute("data-forType")); }; function makeUI() { data.types.forEach(function(type) { document.querySelector("ul").innerHTML += makeLi(type); }); Array.from(document.querySelectorAll("li")) .forEach(function(el) { el.addEventListener("change", onChange); }); }; 

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