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计算器中的Java inputMismatchException

[英]Java inputMismatchException in calculator

i'm making a calculator but i'm having trouble using the scanner input, i declared the variables as double but if i use i get this error: 我正在做一个计算器,但是在使用扫描仪输入时遇到了麻烦,我将变量声明为double,但是如果我使用,则会出现此错误:

java.util.InputMismatchException
    at java.util.Scanner.throwFor(Unknown Source)
    at java.util.Scanner.next(Unknown Source)
    at java.util.Scanner.nextDouble(Unknown Source)
    at ProgramTUI.main(ProgramTUI.java:49)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at edu.rice.cs.drjava.model.compiler.JavacCompiler.runCommand(JavacCompiler.java:267)

Here's the code: 这是代码:

import java.util.Scanner;
    public class ProgramTUI {

    public static double add(double a, double b) {

      return a+b;
    }

    public static double substract(double a, double b) {

      return a-b;
    }    

    public static double multiply(double a, double b) {

      return a*b;
    }

    public static double divide(double a, double b) {

      return a/b;
    }    

    public static void main(String[] args) {

        int choice;
        double a, b;

        System.out.println("1- Add");
        System.out.println("2- Sub");
        System.out.println("3- Mul");
        System.out.println("4- Div");
        System.out.print("Elige la operacion -");
        Scanner var = new Scanner(System.in);

        choice = var.nextInt();
        System.out.print("Introduce el primer numero -");
        a = var.nextDouble();
        System.out.print("Introduce el segundo numero -");
        b = var.nextDouble();

        switch (choice) {
            case 1:
                System.out.print(add(a,b));
                break;

            case 2:
                System.out.print(substract(a,b));
                break;

            case 3:
                System.out.print(multiply(a,b));
                break;

            case 4:
                System.out.print(divide(a,b));
                break;
        }
    }
}

With int numbers the program work just fine, i declared a and b with var.nextDouble(); 使用int数字,程序运行正常,我用var.nextDouble()声明了a和b; so i don't know what's going on. 所以我不知道发生了什么。

我相信您使用的是错误的小数点分隔符,请尝试如下操作:

Scanner var = new Scanner(System.in).useLocale(Locale.ENGLISH); 

You program will fail if whatever you input can not be interpreted as int for var.nextInt(); 如果您输入的任何内容都不能解释为var.nextInt(); int,则程序将失败var.nextInt(); and double for var.nextDouble(); 并为var.nextDouble();加倍var.nextDouble();

This might be due to the system locale having another number format. 这可能是由于系统区域设置具有其他数字格式。

You can use this to force the English format: 您可以使用它来强制使用英语格式:

Scanner var = new Scanner(System.in).useLocale(Locale.ENGLISH); 

Or you can get the Numbers as strings and parse them 或者,您也可以将数字作为字符串进行解析

      try 
      {  
         value = Integer.parseInt(value);  
      } 
      catch (NumberFormatException e) 
      {  
         conversionfailed = true;  
      }  

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