while循环中仅显示一个结果

Question

I'm trying to show all results from the database, but to show "None" if there are no results. However, when I run my code I only get a single result instead of the two that are currently there. I can't figure out what I am doing wrong.

$select1 = mysqli_query($connect, "SELECT * FROM `update` WHERE did='joined'");
$num_rows = mysqli_num_rows($select1);
if ($num_rows==0) {
    $joined="None";
}else{
    while($row=mysqli_fetch_assoc($select1)) {
        $joined=$row['name'].", ";
    }
}
echo $joined;

Answer 1

You are over writing the data you process in the while loop by using $joined = $row['name'].", ";

Instead concatenate all occurances onto the string using the .= operator

while($row=mysqli_fetch_assoc($select1)) {
    $joined .= $row['name'].", ";
}