Excel：除以逗号分隔的单个单元格数字

Question

I have a string of numbers in a single Excel cell separated by commas, eg A2 = "4,3,2,7" . I want a formula to be able to divide those number by 2 in cell B2 , eg B2 = "2,1,1,3" (odd numbers should round down rather than up)

The formula needs to be able to account for:
- smaller or larger string of numbers
- for both single and double digit numbers
- numbers that are even or odd
- no VBA
- formula can use multiple columns but not the delimited text to columns feature (due to cell location)

I was able to get a formula to sum the string of numbers in A2 (4,3,2,7 = 16) but not able to divide by 2. My formula to sum the string is below. Any help is appreciated, thanks!

{=SUM(IF(ISERR(VALUE(MID(A2,ROW($A$1:OFFSET($A$1,LEN(A2)-1,0‌​)),1))),0,VALUE(MID(‌​A2,ROW($A$1:OFFSET($‌​A$1,LEN(A2)-1,0)),1)‌​)))}

Answer 1

In your example, use this formula into cell B1 :

=SUBSTITUTE(SUBSTITUTE(A1,",","000")/2,"000",",")

Then result will be like this:

 |    A    |    B    |
 +---------+---------+  
1| 4,2,6,8 | 2,1,3,4 |
2|

Answer 2

Well, This is my second attempt to solve(I hope) your problem. If your string is in cell A2 , then put this code inot cell B2 :

=LEFT(IFERROR(ROUNDDOWN(MID(A2,1,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,3,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,5,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,7,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,9,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,11,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,13,1)/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,15,1)/2,0),""),LEN(A2))

It can be worked with up to 8 number string, as well as odd numbers.

Update

This formula can handle double digit numbers but it supports only from 1 to 4 string numbers(eg (25,5,36,48)):

=LEFT(IFERROR(ROUNDDOWN(MID(A2,1,IFERROR(SEARCH(",",A2,1)-1,LEN(A2)))/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,SEARCH(",",A2,1)+1,IFERROR(SEARCH(",",A2,SEARCH(",",A2,1)+1)-SEARCH(",",A2,1)-1,LEN(A2)-SEARCH(",",A2,1)))/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,SEARCH(",",A2,SEARCH(",",A2,1)+1)+1,IFERROR(SEARCH(",",A2,SEARCH(",",A2,SEARCH(",",A2,1)+1)+1)-SEARCH(",",A2,SEARCH(",",A2,1)+1)-1,LEN(A2)-SEARCH(",",A2,SEARCH(",",A2,1))))/2,0),"")&","&IFERROR(ROUNDDOWN(MID(A2,SEARCH(",",A2,SEARCH(",",A2,SEARCH(",",A2,1)+1)+1)+1,IFERROR(SEARCH(",",A2,SEARCH(",",A2,SEARCH(",",A2,SEARCH(",",A2,1)+1)+1)+1)-SEARCH(",",A2,SEARCH(",",A2,SEARCH(",",A2,1)+1)+1)-1,LEN(A2)-SEARCH(",",A2,SEARCH(",",A2,SEARCH(",",A2,1)+1)+1)))/2,0),""),LEN(A2))