如何使用SQL查询从表中查找倒数第二条记录？

Question

I have student table and there is 10 record in this table. But I want to find out the second last record and I have only table name so how can I found that record?

here is my query .

select * 
from student 
order by primarykey desc LIMIT 1,1

Thanks in advance.

Answer 1

You can do it like this:

SELECT * FROM (
                SELECT *,ROW_NUMBER() OVER (PARTITION BY PrimaryKey DESC) AS RN
                ) X
WHERE X.RN=2

The sub query will reverse your result according to primary key and return the row_number() along with it, from that result set you are taking the 2nd row which will be the actual 2nd last record.

Answer 2

The ANSI standard SQL method is:

select * 
from student 
order by primarykey desc
offset 1 row
fetch first 1 row only;

This is now supported in many, if not most, databases.

Answer 3

Should it :

SELECT TOP 1 * FROM
(SELECT Top 2 * FROM student ORDER BY primarykey DESC) x                     
ORDER BY primarykey

Answer 4

Use below query:

 select top 1 * from [Your_Table_Name] where [Your_Table_Primary_Name] in
     (select top 3 [Your_Table_Primary_Name] from [Your_Table_Name] order by
      [Your_Table_Primary_Name] desc) 
order by [Your_Table_Primary_Name] asc

Description

---

1. first you need to select last three records using bellow syntax

 select top 3 [Your_Table_Primary_Name] 
 from [Your_Table_Name] 
 order by [Your_Table_Primary_Name] desc

2. after then you need to select first record using bellow syntax

 select top 1 * 
 from [Your_Table_Name] 
 where [Your_Table_Primary_Name] in (***First Syntax/Above described Syntax*****) 
 order by [Your_Table_Primary_Name] asc