[英]Regex Pattern match to find and replace
I am trying to create a regex pattern to find and then replace my IMG src tags in my HTML template. 我正在尝试创建一个正则表达式模式,以查找然后替换我的HTML模板中的IMG src标记。
Essentially, the pattern should find the contents of the src: 本质上,该模式应该找到src的内容:
And then replace it as such: none 然后将其替换为:none
In above code source is always same data-lazy-src is chnaging 在上面的代码源中,总是在更改data-lazy-src
I'll agree that regex isn't necesarily the right way to do this. 我同意正则表达式不一定是正确的方法。 Here is a solution using the HTML Dom parser: 这是使用HTML Dom解析器的解决方案:
$html = 'your markup';
$doc = new DOMDocument();
$doc->loadHTML($html);
$tags = $doc->getElementsByTagName('img');
if(count($tags) > 0) {
$tag = $tags->item(0);
$tag->setAttribute('src', $new_src_url);
$doc->saveHTML($tag);
}
Then, $doc
should have your updated markup with the src atributes of your images changed. 然后, $doc
应该使用图像的src属性更改更新的标记。
尝试如下操作:
preg_replace('/(<img.*) src=\"[^"]*\"(.*>)/', '$1 src="none"$2', $html)
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