[英]String.endsWith(/[string]/[1-999]/)
I'm trying to parse the end of a url and redirect depending on it's ending. 我正在尝试解析url的结尾并根据其结尾进行重定向。
For example, if I'm going to www.something.com/foo/1/
I want to redirect to www.something.com/foo/1/bar
. 例如,如果我要去
www.something.com/foo/1/
我想重定向到www.something.com/foo/1/bar
。 The 1 in this case can be any positive integer. 在这种情况下,1可以是任何正整数。
What I've been trying with but can't get to work is: 我一直在尝试但无法正常工作的是:
if (window.location.href.endsWith('/foo/\\d/')) { fetch stuff and redirect } else { do something else }
Which doesn't work, I'm guessing endsWith
can't parse regex. 这是行不通的,我猜
endsWith
不能解析正则表达式。
Thanks in advance, 提前致谢,
Peter 彼得
In your code endsWith('/foo/\\d/')
check the string is ending with that particular string argument and won't work as a regex. 在您的代码
endsWith('/foo/\\d/')
检查字符串是否以该特定字符串参数结尾,并且不能用作正则表达式。
For checking using regex use RegExp#test
method with regex /foo\\/\\d{1,3}\\/$/
. 要使用正则表达式进行检查,请对Regex
/foo\\/\\d{1,3}\\/$/
使用RegExp#test
方法。
if(/foo\/\d{1,3}\/$/.test(window.location.href))
You can regex match for the end of string instead, 您可以将正则表达式匹配为字符串的结尾,
/.*foo\d/$/
My regex might be wrong, but you can use the $ to denote end of string and just do a regular regex.test 我的正则表达式可能是错误的,但是您可以使用$表示字符串的结尾,而只需执行常规的regex.test
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