Node.js将JOIN用于序列表上的两个表

Question

I'm trying to implementing this mysql command on sequelize, but as far as i'm newbie to use this library i can't implementing that

i want to make this sql command:

SELECT * FROM users 
join users_contacts_lists on users_contacts_lists.mobile_number = users.mobile_number 
WHERE users_contacts_lists.user_id = 1

My models to create database schema:

'use strict';
var config = require('../config');

var User = config.sequelize.define('users', {
    id: {
        type: config.Sequelize.INTEGER,
        autoIncrement: true,
        primaryKey: true
    },
    password: {
        type: config.Sequelize.STRING
    },
    username: {
        type: config.Sequelize.STRING
    },
    mobileNumber: {
        type: config.Sequelize.STRING,
        field: 'mobile_number'
    },
    status: {
        type: config.Sequelize.STRING
    },
}, {freezeTableName: true});

var UsersContactsLists = config.sequelize.define('users_contacts_lists', {
    id: {
        type: config.Sequelize.INTEGER,
        autoIncrement: true,
        primaryKey: true
    },
    userId: {
        type: config.Sequelize.INTEGER,
        field: 'user_id'
    },
    mobileNumber: {
        type: config.Sequelize.STRING,
        field: 'mobile_number', defaultValue: 0
    }
}, {freezeTableName: true});

UsersContactsLists.belongsTo(ChannelsTypes, {foreignKey: 'user_id'});
User.hasMany(Channels, {foreignKey: 'id'});

User.sync();
UsersContactsLists.sync();

module.exports =
{
    users: User,
    usersContactsLists: UsersContactsLists
};

how can i resolve this problem? Thanks in advance

Answer 1

you can define the target key and the foreign key both in a relation like this :

User.belongsTo(UsersContactsLists, {targetKey:'mobileNumber',foreignKey: 'mobileNumber'});

then you can use this :

User.findAll({
include: [{
    model: UsersContactsLists,
    where: {
        userId: 1
    }
}]

Answer 2

Fiddled around a bit, does this statement do what you want?

User.findAll({
    include: [{
        model: UsersContactsLists,
        where: {
            userId: 1
        }
    }]