将数据从SQL数据库存储到PHP表中时出错

Question

I am learning PHP and SQL, and I am currently trying to output data from a preexisting SQL database table into a table created via PHP. As of now, I am just trying to get the data from a single column and output the data into a column in my PHP table. I am able to correctly gather the data one row at a time using the code:

"SELECT column FROM table WHERE row1='variable1' AND row2='variable2'"

with WHERE pinpointing which row should be outputted within column .

However, I am having issues with storing the data to output the proper result. I am currently using the code below to output the row with the data from the SQL table:

if($con->query("SELECT column FROM table WHERE row1='variable1' AND row2='variable2'")) {
    if($output= $con->use_result()) {
        while($row = $output->fetch_assoc()) {
            echo "<td>".$output."</td>";
    }
}}

However, when I run the code, it merely blanks the row where I should be outputting the data. Could anyone please point me in the right direction to properly store and output the row into a table? It would be much appreciated. Let me know if anymore of my code or other information is needed.

EDIT: I should mention that the table is being generated via an HTML button.

Answer 1

Please try again..

if($con->query("SELECT column FROM table WHERE row1='variable1' AND row2='variable2'")) {
    if($output= $con->use_result()) {
        while($row = $output->fetch_assoc()) {
            echo "<td>".$row['row1']."</td>";
            echo "<td>".$row['row2']."</td>";
    }
}}

Answer 2

I tried the following code and it worked for me. This has also been suggested in the comments above:

if($con->query("SELECT column FROM table WHERE row1='variable1' AND row2='variable2'")) {
    if($output= $con->use_result()) {
        while($row = $output->fetch_assoc()) {
            echo "<td>".$row['column']."</td>";
        }
    }
}

Answer 3

I was actually able to fix my code, with some help from the code used here. The primary issue was that I used:

if($con->query("SELECT column FROM table WHERE row1='variable1' AND row2='variable2'"))

I was able to fix my code by using:

$sql = "SELECT column FROM table WHERE row1='variable1' AND row2='variable2'"; $output = $con->query($sql);

before the if statement. I appreciate the help!