int A [] = {}在C中意味着什么？

Question

I came across this piece of code. It doesn't give an error, but what exactly does it mean?

int A[]={};

EDIT: I had to edit this post because some of you asked for context, compiler and so on..

I do not know much about compilers but i managed to found the version i'm using "gcc (tdm-1) 4.9.2".

I have tried the code myself and it did run correctly, i was also able to read and write on the array. My question is : What exactly happens when i declare such an array ?

Answer 1

int A[]={};

is illegal in C. Empty initializers are not valid. See C11 draft, 6.7.9 Initialization .

Answer 2

It means nothing, it is not valid C.

C11 6.7.9 states that the two following forms are valid:

{ initializer-list } 
{ initializer-list , }

where initializer-list is defined as one of the following:

designationopt initializer
initializer-list , designationopt initializer

This could either be an assignment expression or a C99 designated initializer. An empty initializer list is not valid syntax.

Answer 3

它定义了一个int类型的空数组。

Answer 4

You should show some more context, and mention which compiler was being used.

I don't think that code compiles with a standards-compliant compiler, the empty initializer list makes it invalid.