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函数的静态局部变量对象在哪里定义?

[英]Where is a static local variable object of function defined?

I know that static member variables have to be defined out of the class somewhere (not in a header - in a TU), but I'm wondering then why the following works 我知道静态成员变量必须在类之外的某个地方定义(而不是在标头中-在TU中),但是我想知道为什么下面的方法可行

#include <iostream>

class Logger {
public:
  static const Logger& GetInstance() {
    static Logger logger; // ??
    return logger;
  }

  void hello() const {
      std::cout << "Hello";
  }

private:
  Logger() {

  }
};


const Logger& logger = Logger::GetInstance();

int main(int argc, char* argv[]) {

  logger.hello();

  return 0;
}

Where is the object associated with logger defined? logger关联的对象在哪里定义? And why doesn't a function static variable require a definition/instantiation point as for a static class member variable? 为什么函数静态变量不像静态类成员变量那样需要定义/实例化点?

You do define it: in the function GetInstance() . 确实定义了它:在函数GetInstance()

It's just that luck is on your side: that function is only encountered in exactly one translation unit (you've put the class definition in a source file), so the linker is not going to moan. 这只是运气就在你身边:该功能仅在只有一个翻译单位遇到的(你已经把类定义在源文件),因此链接器不会抱怨。

It would have been a different matter if the code were in a header and included in more than one translation unit. 如果代码位于标头中并且包含在多个翻译单元中,那将是另一回事。

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