C：scanf_s忽略“％n”（读取的字符数）

Question

I want to read a string using scanf and get the actual str length and then realloc it afterward. I've read that %n gives the number of chars read , so that's what I need. Visual Studio asks me to use scanf_s , where after each string you must specify it's buffer size.

I write:

int actual_length;
scanf_s("%[^\n]s%n", str, MAX_STRING_LEN, &actual_length);
printf("actual length = %d\n", actual_length);

I get:

actual length = -858993460

So, when I added this %n nothing happened. If I take away just the %n it says too many args, if I take away just the &actual_length it says too few args. If I take away both the result is the same, obviously.

I tried to google for like 40 mins and I'm stuck. MSDN doesn't say anything specific about scanf_s treating %n .

Answer 1

BLUEPIXY answered this question in the comments:

" %[^\\n]s%n " --> " %[^\\n]%n "

In this case, s is not correct. s is a designation that it isn't conversion specifier. It is interpreted as a matched character. However, since matching characters do not actually exist, Input will fail at s . So %n is not interpreted.