[英]Mismatched types for returned struct (expected <K, V>, found <&K, &V>)
Given the following code (which doesn't do much yet): 给出以下代码(目前尚不完善):
use std::collections::BTreeMap;
use std::iter::FromIterator;
trait Node<K, V> {
fn split(&self) -> Split<K, V>;
}
#[derive(Debug, Copy, Clone)]
pub struct Config {
data_b: usize,
}
struct Split<'a, K, V> {
left: Box<Node<K, V> + 'a>,
right: Box<Node<K, V> + 'a>,
}
#[derive(Debug)]
pub struct DataNode<K, V> {
cfg: Config,
children: BTreeMap<K, V>,
}
impl<K: Clone + Ord, V: Clone> Node<K, V> for DataNode<K, V> {
fn split(&self) -> Split<K, V> {
let data_b = self.cfg.data_b;
Split {
left: Box::new(DataNode {
cfg: self.cfg.clone(),
children: BTreeMap::from_iter(self.children.iter().take(data_b))
}),
right: Box::new(DataNode {
cfg: self.cfg.clone(),
children: BTreeMap::from_iter(self.children.iter().rev().take(data_b))
}),
}
}
}
The compiler gives the following error: 编译器给出以下错误:
error[E0308]: mismatched types
--> lib.rs:68:9
|
68 | Split {
| ^ expected type parameter, found &K
|
= note: expected type `Split<'_, K, V>`
= note: found type `Split<'_, &K, &V>`
I'm pretty new to Rust so I'm not sure what's causing this. 我对Rust还是很陌生,所以我不确定是什么原因造成的。 To be absolutely clear, the question I'm having is not about what the error message means .
绝对清楚地说,我所遇到的问题与错误消息的含义 无关 。 Clearly, it means that I'm not returning the right type.
显然,这意味着我没有返回正确的类型。 The question is why does the compiler interpret this
Split {...}
code as code that returns Split<'_, &K, &V>
when I expect it to be Split<'_, K, V>
. 现在的问题是,为什么编译器解释这种
Split {...}
代码返回代码Split<'_, &K, &V>
时,我希望它是Split<'_, K, V>
Any insight is appreciated. 任何见解均表示赞赏。
The references come from where you iterate on the child to build a new BTreeMap
: 引用来自您在子级上迭代以构建新的
BTreeMap
:
BTreeMap::from_iter(self.children.iter().take(data_b))
If you look at the iterator returned by BTreeMap::iter()
, the Item
type is: 如果查看
BTreeMap::iter()
返回的迭代器 ,则Item
类型为:
type Item = (&'a K, &'a V)
ie the iterator returns pairs of references to the contents. 即,迭代器返回对内容的引用对。 This makes sense, because you don't want to move items out of the map when iterating, or rely on
Copy
. 这是有道理的,因为您不想在迭代时将项目移出地图,也不必依靠
Copy
。
This is slightly different from eg Vec::iter()
, being a pair of references rather than a reference to a pair. 这与例如
Vec::iter()
稍有不同, Vec::iter()
是一对引用而不是一对引用。 This does make sense, as a reference to a pair would mean the container would have to actually contain those pairs internally (restricting the internal data structure). 这确实是有道理的,因为对对的引用意味着容器将必须实际上在内部包含那些对(限制内部数据结构)。
The simplest thing is to clone the key and value: 最简单的事情是克隆键和值:
BTreeMap::from_iter(self.children.iter()
.map(|(&a, &b)| (a.clone(), b.clone()))
.take(data_b))
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