计算从每年二月的第一个星期日开始的一年中的第一周

Question

I have an issue here. I want to calculate the week nummber of first sunday of business year. Where I work their calendar starts on February 1st. To calculate i have a column A2 in excel which has the date in mm/dd/yyyy format. I want to generate the corresponding fiscal week for the column.

example of my result set:

for 2/1/15 the week of year number should be 1 For 2/7/16 the week number of year should be 1

I tried the below formula, but its starting the week from the first day of the fiscal year and not the first sunday of the year.

=INT((A1-WEEKDAY(E9165)-DATE(YEAR(A1+7-WEEKDAY(A1))-(MONTH(A1)<2),2,1))/7)+2

Please help...

-Sandra

Answer 1

Assuming that your work years always start on the first sunday after February 1st:

=IF(WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1)<=0,52+WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1),WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1))

We first determine the week number of the date starting from the first Sunday of February. To do this I have used WEEKNUM()-WEEKNUM(02/01/SAMEYEAR) taking 1 day from the date to force week 1 as Excel begins counting from week 0 by default. Using IF() we state that if the outcome is 0 or less then add the result to 52, which will give us the correct result for dates in January as they produce negative values.

Edit - Very long formula but gives you the week of the quarter in Q1 W1 format:

=SUBSTITUTE(CONCATENATE("Q",INT(IF(WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1)<=0,52+WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1),WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1))/13)+(IF(INT(IF(WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1)<=0,52+WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1),WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1))-INT((IF(WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1)<=0,52+WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1),WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1))/13))*13)=0,0,1))," W",INT(IF(WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1)<=0,52+WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1),WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1))-INT((IF(WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1)<=0,52+WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1),WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1))/13))*13)),"W0","W1")

Apologies for the length, I tried multiple methods to try to find a neater solution, but this was all that I could get to work. It would be a lot neater if there were multiple columns used.

Answer 2

使用这个公式：

=IF(A1>=IF(WEEKDAY(DATE(YEAR(A1),2,1),1)=1,DATE(YEAR(A1),2,1),DATE(YEAR(A1),2,7-WEEKDAY(DATE(YEAR(A1),2,1),1)+2)),ROUNDUP((A1-IF(WEEKDAY(DATE(YEAR(A1),2,1),1)=1,DATE(YEAR(A1),2,1),DATE(YEAR(A1),2,7-WEEKDAY(DATE(YEAR(A1),2,1),1)+2))+1)/7,0),ROUNDUP((A1-IF(WEEKDAY(DATE(YEAR(A1),2,1),1)=1,DATE(YEAR(A1)-1,2,1),DATE(YEAR(A1)-1,2,7-WEEKDAY(DATE(YEAR(A1)-1,2,1),1)+2))+1)/7,0))

Answer 3

Way late to the party but was looking for the answer and found this thread. Ended up play around with the function myself and it's much easier to just deduct the dates; =WEEKNUM("date"- days you wish to offset)

Ex; If cell A1 holds my date, 2/1/2021 I wish to convert; =WEEKNUM(A1-31) result "1".