[英]pass and modify char array[][] in function C
i have a char array[][] and i want to use it at a void function and modify some values. 我有一个char数组[] [],我想在void函数上使用它并修改一些值。
char teams[MAX_TEAMS][MAX_NAME_LENGTH + 1] = { "Olympiakos", "P.A.O.K.", "Panathinaikos", "Panionios"};
(MAX_TEAMS and MAX_NAME_LENGTH are #defined integers at the start of the programm. And i was to use a void function to modify the array.How do i have to define the function,how am i goin to pass the array from main?and how am i goin to use it in the function?? (MAX_TEAMS和MAX_NAME_LENGTH是程序开头的#defined整数。而且我要使用void函数来修改数组。如何定义函数,如何从main传递数组?以及如何我要在功能中使用它吗?
void print_teams(char [][]); (?????)
int main(){
char teams[MAX_TEAMS][MAX_NAME_LENGTH + 1] = { "Olympiakos", "P.A.O.K.", "Panathinaikos", "Panionios"};
print_teams(teams);
}
void print_teams(char teams[MAX_TEAMS][MAX_NAME_LENGTH+1]){
strcpy(teams[0], "Milan FC");
}
I am looking for a way of declaration so that any modifies inside the void function to be saved at array teams.
Thanks in advance!
Inside the function teams[0]
is an array. 在功能
teams[0]
是一个数组。 You can't assign to an array, only copy to it: 您不能分配给数组,只能复制到数组:
strcpy(teams[0], "Milan FC");
Also note the use of double quotes. 还请注意使用双引号。
Lastly for the function prototype, just copy the declaration you have for the function definition. 最后,对于函数原型,只需复制函数定义中的声明即可。
Best Way to do this : 最佳方法:
void print_teams(char [][MAX_COL_SIZE]);
you can find more info in the below link : http://c-faq.com/aryptr/pass2dary.html 您可以在以下链接中找到更多信息: http : //c-faq.com/aryptr/pass2dary.html
and use strcpy(teams[0],"Real Madrid");
并使用
strcpy(teams[0],"Real Madrid");
instead of using "=" 而不是使用“ =”
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