使用 lambda 作为 C++ 函数的参数

Question

I would like to use a lambda as a parameter for a C++ function, but I don't know which type to specify in the function declaration. What I would like to do is this:

void myFunction(WhatToPutHere lambda){
    //some things
}

I have tried void myFunction(auto lambda) and void myFunction(void lambda) but none of these codes compiled. In case it matters, the lambda doesn't return anything.

How can I use a lambda as a parameter in a C++ function?

Answer 1

You have 2 ways: make your function template:

template <typename F>
void myFunction(F&& lambda)
{
    //some things
}

or erase type (with std::function for example):

void
myFunction(const std::function<void()/*type of your lamdba::operator()*/>& f)
{
    //some things
}

Answer 2

You have two choices, basically.

Make it a template:

template<typename T>
void myFunction(T&& lambda){
}

or, if you do not want (or can't) do that, you can use type-erased std::function :

void myFunction(std::function<void()> const& lambda){
}

---

Conversely, your attempt with auto would've been correct under the concepts TS as currently implemented in gcc, where it'd be an abbreviated template .

// hypothetical C++2x code
void myFunction(auto&& lambda){
}

or with a concept:

// hypothetical C++2x code
void myFunction(Callable&& lambda){
}

Answer 3

If this is an inline function, prefer a template, as in

template<typename Func>
void myFunction(Func const&lambda)
{
    //some things
}

because it binds to anything that makes sense (and will cause compiler error for anything else), including lambdas, instances of named classes, and std::function<> objects.

On the other hand, if this function is not inline , ie implemented in some compilation unit, you cannot use a generic template but must use a specified type, which is best taken a std::function<> object and passed via reference.

Answer 4

Pass it as you'd pass a simple function. Just give it a name with auto

#include <iostream>

int SimpleFunc(int x) { return x + 100; }
int UsingFunc(int x, int(*ptr)(int)) { return ptr(x); }
auto lambda = [](int jo) { return jo + 10; };

int main() {
    std::cout << "Simple function passed by a pointer: " << UsingFunc(5, SimpleFunc) << std::endl;
    std::cout << "Lambda function passed by a pointer: " << UsingFunc(5, lambda) << std::endl;

}

Output:
Simple function passed by a pointer: 105
Lambda function passed by a pointer: 15