如何删除非字母数字字符？

Question

I need to remove all characters from a string which aren't in az AZ 0-9 set or are not spaces.

Does anyone have a function to do this?

Answer 1

Sounds like you almost knew what you wanted to do already, you basically defined it as a regex.

preg_replace("/[^A-Za-z0-9 ]/", '', $string);

Answer 2

For unicode characters, it is:

preg_replace("/[^[:alnum:][:space:]]/u", '', $string);

Answer 3

Regular expression is your answer.

$str = preg_replace('/[^a-z\d ]/i', '', $str);

• The i stands for case insensitive.
• ^ means, does not start with.
• \d matches any digit.
• az matches all characters between a and z . Because of the i parameter you don't have to specify az and AZ .
• After \d there is a space, so spaces are allowed in this regex.

Answer 4

here's a really simple regex for that:

\W|_

and used as you need it (with a forward / slash delimiter).

preg_replace("/\W|_/", '', $string);

Test it here with this great tool that explains what the regex is doing:

http://www.regexr.com/

Answer 5

[\W_]+

$string = preg_replace("/[\W_]+/u", '', $string);

It select all not AZ, az, 0-9 and delete it.

See example here: https://regexr.com/3h1rj

Answer 6

If you need to support other languages, instead of the typical AZ, you can use the following:

preg_replace('/[^\p{L}\p{N} ]+/', '', $string);

• [^\p{L}\p{N} ] defines a negated (It will match a character that is not defined) character class of:
  • \p{L} : a letter from any language.
  • \p{N} : a numeric character in any script.
  • : a space character.
• + greedily matches the character class between 1 and unlimited times.

This will preserve letters and numbers from other languages and scripts as well as AZ:

preg_replace('/[^\p{L}\p{N} ]+/', '', 'hello-world'); // helloworld
preg_replace('/[^\p{L}\p{N} ]+/', '', 'abc@~#123-+=öäå'); // abc123öäå
preg_replace('/[^\p{L}\p{N} ]+/', '', '你好世界!@£$%^&*()'); // 你好世界

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^{Note: This is a very old, but still relevant question. I am answering purely to provide supplementary information that may be useful to future visitors.}

Answer 7

preg_replace("/\W+/", '', $string)

You can test it here: http://regexr.com/

Answer 8

I was looking for the answer too and my intention was to clean every non-alpha and there shouldn't have more than one space.
So, I modified Alex's answer to this, and this is working for me preg_replace('/[^az|\s+]+/i', ' ', $name)
The regex above turned sy8ed sirajul7_islam to sy ed sirajul islam
Explanation: regex will check NOT ANY from a to z in case insensitive way or more than one white spaces, and it will be converted to a single space.

Answer 9

You can split the string into characters and filter it.

<?php 

function filter_alphanum($string) {
    $characters = str_split($string);
    $alphaNumeric = array_filter($characters,"ctype_alnum");
    return join($alphaNumeric);
}

$res = filter_alphanum("a!bc!#123");
print_r($res); // abc123

?>