[英]Publish Azure Application with MS-Build on vs2015
I am trying to publish my application (mvc and webapi2) using visual studio on Azure App Services. 我正在尝试使用Azure App Services上的Visual Studio发布我的应用程序(mvc和webapi2)。 Everything working fine when I publish the normal structure. 发布正常结构时,一切工作正常。
Then I tried to add a folder that is not a part of my solution (generates and changes by front-enders some how) so I've added the required folder to msbuild and everything works fine when I publish to a normal profile (local folder). 然后,我尝试添加一个不属于我的解决方案的文件夹(由前端渲染器生成并更改某些内容),因此我已将所需的文件夹添加到msbuild中,并且在发布到普通配置文件(本地文件夹)时一切正常)。
On the next step, I try to publish the project on the azure, where I saw that it won't publish files that I've added to ms-build. 下一步,我尝试在Azure上发布项目,在那里我看到它不会发布我添加到ms-build的文件。 How to fix it? 如何解决?
I've googled it and I've found this: Publish Azure Application with MSBuild and the answer is to publish using Power shell. 我用Google搜索它,发现了这一点: 使用MSBuild发布Azure应用程序,答案是使用Power Shell发布。
But the link is 2 years old and I Azure matured a lot in this 2 years. 但是链接已有2年历史了,而我Azure在这2年中已经成熟了很多。 Is there any way to do it using visual studio? 使用Visual Studio有什么方法吗?
please note that this is not a duplicate of Publish Azure Application with MSBuild since it is 2 years later, and on vs 2015 and Azure sdk is 2.9 not 2.2. 请注意 ,这不是使用MSBuild的发布Azure应用程序的副本,因为它是2年后的版本,而与2015和Azure sdk相比则是2.9而不是2.2。
And if you don't agree, or anything please comment. 如果您不同意,请发表评论。
Yes, we can do it using Visual Studio. 是的,我们可以使用Visual Studio做到这一点。 Please have a try to add following code in the project file .I create a demo for it, the following is my detail steps. 请尝试在项目文件中添加以下代码。我为此创建了一个演示,以下是我的详细步骤。
<ItemGroup>
<Content Include="C:\test\**">
<Link>test\%(RecursiveDir)%(Filename)%(Extension)</Link>
<CopyToOutputDirectory>PreserveNewest</CopyToOutputDirectory>
</Content>
</ItemGroup>
Create MVC project vis visual studio 通过Visual Studio创建MVC项目
Unload the project from the solution via right click the project name. 通过右键单击项目名称从解决方案中卸载项目。
Update: Use target to do that 更新:使用目标来做到这一点
<Target Name="CopyFiles" BeforeTargets="PrepareForBuild">
<Copy SourceFiles="@(MySourceFiles)" DestinationFiles="@(MySourceFiles->'C:\Tom\MSBuild\MSBuild\test\%(RecursiveDir)%(Filename)%(Extension)')" />
</Target>
<Target Name="BeforeBuild">
<ItemGroup>
<Content Include="test\**\*.*" />
</ItemGroup>
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