有没有一种方法可以比较字符串中的字符。 蟒蛇？

Question

I am wondering if there is a way that I can compare the first letter of the string to the second; then the third to the forth ... etc. At the moment I have this:

a=0
b=0
string = "GG EZ"
if string[a:b] == string[a+1:b+1]:
    print("hello")

It works but is there a more efficient way of doing it?

Answer 1

You can use zip to pair up the elements

s = "GGEZ"
for a, b in zip(*[iter(s)]*2):
    if a==b:
        print('Hello')

More on this usage of zip here

Answer 2

string = "GG EZ abbdff"

for i in range(0, len(string), 2):
    if string[i] == string[i+1]:
        print("characters match")

Create a range of every second character in the string. Iterate over the range and compare character at the index i with the following.

Edit: If your string length is an odd number you run into an out of range exception. I let you figure that one out by yourself :)