按应用程序图标后，在android中启动上次打开的活动

Question

I have the following constellation:

Press App Icon open Activity A , which checks which activity should open next (Registration or Main Activity B ). A is marked as Main Launcher in the xml. Now I go to B . Then I have a user action and come to Activity C . Now I press home. If I chose the app again from background task selector i come back to C . But when I instead press the app icon again,I will start again with A . Is it possible to handle it in manifest that in this case C should open again or do I have to care it by myself (eg via SharedPreferences?)

Answer 1

This behavior can be controlled in the manifest via android:launchMode .

See here: https://developer.android.com/guide/topics/manifest/activity-element.html#lmode and more explanation here: https://developer.android.com/guide/components/tasks-and-back-stack.html

for your scenario, you'd want to keep C and route new intents to the existing instance of it, so this might work:

<activity
   android:name="A"
   ...
   android:launchMode="singleTask" />
<activity
   android:name="B"
   ...
   android:launchMode="singleTask" />
<activity
   android:name="C"
   ...
   android:launchMode="singleTask" />