Oracle SQL分组依据

Question

I have below data in my table,

    Id month value

    1  Jun  20
    1  Jul  22
    1  Aug  0
    1  Sep  12
    2  Jun  21
    2  Jul  45

I need to group them as

Id Jun Jul Aug Sep
1   20  22 0   12
2   21  45

I am not sure what syntax i should use. Help appreciated

Answer 1

@Gurwinder's answer is workable. Also you can use pivot (in Oracle 11 or above):

select *
 from (
  select id, month, value
    from your_table    
)
pivot (
      max(value)
      for month in ('Jun' as "Jun", 'Jul' as "Jul", 'Aug' as "Aug", 'Sep' as "Sep")
)t

Answer 2

Please try below:

select id,
    sum(decode(month, 'Jun', value)) jun,
    sum(decode(month, 'Jul', value)) jul,
    sum(decode(month, 'Aug', value)) aug,
    sum(decode(month, 'Sep', value)) sep
from my_table group by id

Answer 3

You did not mention the version of Oracle. If you are using Oracle 11g or above, the following example would get you close.

create table pivot_test (id number(1), month varchar2(3), value number(2));

insert into pivot_test values (1, 'Jun', 20);
insert into pivot_test values (1, 'Jul', 22);
insert into pivot_test values (1, 'Aug', 0);
insert into pivot_test values (1, 'Sep', 12);
insert into pivot_test values (2, 'Jun', 21);
insert into pivot_test values (2, 'Jul', 45);
commit;

select *
from (select id, month, sum(value) as value from pivot_test group by id, month)
pivot (SUM(value) for (month) in ('Jun', 'Jul', 'Aug', 'Sep'))
order by id
;

It yields the following result.

        ID      'Jun'      'Jul'      'Aug'      'Sep'
---------- ---------- ---------- ---------- ----------
         1         20         22          0         12
         2         21         45