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AngularJS Form和$ scope不互相更新

[英]AngularJS Form and $scope not updating each other

I am trying to make a very minimalistic form in AngularJS (version 1). 我试图在AngularJS(版本1)中制作一个非常简约的形式。

I am trying to use ng-model and the $scope to update an object I've named fluff . 我正在尝试使用ng-model和$scope更新我已命名为fluff的对象。 Once a user clicks submit it should be used in this $http call. 用户单击提交后,应在此$http调用中使用它。

I'm highly confused I thought ng-model would bind this to the object in the scope. 我非常困惑,我认为ng-model会将其绑定到范围中的对象。 But it always returns a blank cause the $scope.fluff is not updating. 但是它总是返回空白,因为$scope.fluff没有更新。

Yet if I inject {{ fluff.link }} this will update based on the textbox. 但是,如果我注入{{ fluff.link }}它将基于文本框进行更新。

Here is my form in the view: 这是视图中的表单:

    <form name="fluffForm" ng-submit="submitform()">
      <span>Link: <input type="text" name="link" ng-model="form.link"></span>
    <span>Description: <input type="text" name="description" ng-model="form.desc"></span>
      <button type="submit">submit</button>

    </form>
</div>

Here is my controller: 这是我的控制器:

(function(){

    'use strict';

    angular.module('fluff').controller('FormController', FormController);


    FormController.$inject = ['$scope', '$rootScope', '$routeParams', '$window', '$http'];


    function FormController( $scope, $rootScope, $routeParams, $window, $http){

        var form = this;
        $scope.fluff = {}; // form data in json object(?) to be posted to mongo database
        $scope.submitform = function(){
            $scope.fluff.link = form.link; 
            $scope.fluff.description = form.desc; 
            console.log('form-data', $scope.fluff);
            $http({
                method: 'POST',
                url: 'http://fluff.link/share',
                data: $scope.fluff,
                headers: {'Content-type': 'application/x-www-form-urlenconded'}
            }).success(function(data){
                console.log('Call to API was successful');
                if(data.errors){
                    console.log('Data Errors');
                    console.log('error:', $data.errors.name);
                    //show errors  -  part of the response in the REST API have to make this portion up myself
                    $scope.errorName = $data.errors.name;

                } else {
                    console.log('returned share id', data);
                    var fluff = 'fluff/link/'+ data;
                    $window.location.href = fluff;
                }

            });

        }


    }

})();

Here is my route: 这是我的路线:

(function(){

    'use strict';

    angular.module('fluff').config(Config);

    Config.$inject = ['$routeProvider'];

    function Config($routeProvider){

        $routeProvider.when('/', {
            templateUrl: 'views/index.client.view.html',
            controller: 'FormController',
            controllerAs: 'form'
        });

    }

})();

Added some logs from the developer console in chrome: 从Chrome开发者控制台添加了一些日志:

in submitform FormController {link: "test", desc: "test"}
fluff.form.controller.js:24 form-data Object {link: undefined}

Got it to work! 得到它的工作! Will update with my answer when it allows! 允许时将更新我的答案!

So my problem here is that I wasn't using the form controller like I should have. 所以我的问题是我没有像应该使用的那样使用form控制器。

Here I have the template being loaded with the controller as form . 在这里,我将模板与控制器一起加载为form

   $routeProvider.when('/', {
        templateUrl: 'views/index.client.view.html',
        controller: 'FormController',
        controllerAs: 'form'
    });

In the template I have to use form : 在模板中,我必须使用form

<span>Link: <input type="text" name="link" ng-model="form.link"></span>

<span>Description: <input type="text" name="description" ng-model="form.desc"></span>

then in the controller I create a this object: 然后在控制器中创建一个this对象:

var vm = this; 

vm is now linked to form. vm现在已链接到表单。

So now I can do this: 所以现在我可以这样做:

    var fluff = {};
    fluff.link = form.link;
    fluff.description = form.desc;

Now fluff has all the data it needs when my user clicks submit. 现在,当我的用户单击“提交”时,fluff拥有了所需的所有数据。

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