[英]How to get a value from a Json array
I have a function in php that returns this json array, this is the function 我在php中有一个函数返回此json数组,这是该函数
$token = $db->getTokenFromEmail($email);
echo $token;
and this is what i get: 这就是我得到的:
[{"unique_id":"cBuJ-xsDDAo:APA91bHYgPwuwXGVxNMuW_Xs0u5bvbr_QSJq8G1_tZ-nGHOdRB0Nv5ijb2BcaP_wUkpyxwERo7cuQxj89YHjOZdIeIwBOGyeHMP_Ywkg_mocfZQr-CxOzy41i8GKj3X6WFjLZJU4ZcbK"}]
My question is how can I get the value (cBuJ-xsD...)? 我的问题是如何获取值(cBuJ-xsD ...)? I have tried this but it doesn't work
我已经尝试过了,但是没有用
$obj = json_decode($token,true);
echo $obj['unique_id'];
Your token's type is a string, and you are correct to use json_decode
. 令牌的类型是字符串,并且正确使用
json_decode
。
If you try to var_dump
the value you will get: 如果尝试使用
var_dump
值,则会得到:
$token = '[{"unique_id":"cBuJ-xsDDAo:APA91bHYgPwuwXGVxNMuW_Xs0u5bvbr_QSJq8G1_tZ-nGHOdRB0Nv5ijb2BcaP_wUkpyxwERo7cuQxj89YHjOZdIeIwBOGyeHMP_Ywkg_mocfZQr-CxOzy41i8GKj3X6WFjLZJU4ZcbK"}]';
$obj = json_decode($token,true);
var_dump($obj);
And the output is: 输出为:
array(1) {
[0]=>
array(1) {
["unique_id"]=>
string(152) "cBuJ-xsDDAo:APA91bHYgPwuwXGVxNMuW_Xs0u5bvbr_QSJq8G1_tZ-nGHOdRB0Nv5ijb2BcaP_wUkpyxwERo7cuQxj89YHjOZdIeIwBOGyeHMP_Ywkg_mocfZQr-CxOzy41i8GKj3X6WFjLZJU4ZcbK"
}
}
You can see that the $obj
variable is an array, and it's first element is another array that has the unique_id
key. 您可以看到
$obj
变量是一个数组,并且它的第一个元素是另一个具有unique_id
键的数组。
To get to that you should use: 为此,您应该使用:
$obj[0]['unique_id'];
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