[英]Crosstab function in postgres not returning any values in table
I'm trying to create a pivot table in pgadmin 4 using the crosstab function. 我正在尝试使用交叉表功能在pgadmin 4中创建数据透视表。 I've successfully created one by copying code (see below) from a postgres manual just to make sure the tablefunc extension was installed / able to work correctly: 我已经通过从postgres手册中复制代码(如下所示)成功创建了一个代码,只是为了确保tablefunc扩展已安装/能够正常工作:
create table sales(year int, month int, qty int);
insert into sales values(2007, 1, 1000);
insert into sales values(2007, 2, 1500);
insert into sales values(2007, 7, 500);
insert into sales values(2007, 11, 1500);
insert into sales values(2007, 12, 2000);
insert into sales values(2008, 1, 1000);
SELECT * FROM crosstab(
$$ SELECT year, month, qty FROM sales ORDER BY 1 $$,
$$ SELECT m FROM generate_series(1,12) m $$
) AS (
year int,
"Jan" int,
"Feb" int,
"Mar" int,
"Apr" int,
"May" int,
"Jun" int,
"Jul" int,
"Aug" int,
"Sep" int,
"Oct" int,
"Nov" int,
"Dec" int
);
year | Jan | Feb | Mar | Apr | May | Jun | Jul | Aug | Sep | Oct | Nov | Dec
------+------+------+-----+-----+-----+-----+-----+-----+-----+-----+------+------
2007 | 1000 | 1500 | | | | | 500 | | | | 1500 | 2000
2008 | 1000 | | | | | | | | | | |
however, when trying to import my own data, the table returns blank values: 但是,当尝试导入我自己的数据时,该表返回空白值:
select *
from medclaims2
output: 输出:
member date paid_amount icd9
1 7/30/2011 43075 ICD9-1
2 8/16/2011 24895 ICD9-2
3 3/7/2012 18957 ICD9-4
4 8/16/2011 37476 ICD9-5
SELECT * FROM crosstab(
$$ SELECT member, icd9, paid_amount FROM medclaims2 $$,
$$ SELECT m FROM generate_series(1,4) m $$
) AS (
member varchar(25), "ICD9-1" varchar(25),"ICD9-2" varchar(25),"ICD9-4" int,"ICD9-5" varchar(25)
);
output: 输出:
member ICD9-1 ICD9-2 ICD9-4 ICD9-5
1
2
3
4
Any help would be much appreciated, thanks! 任何帮助将不胜感激,谢谢!
Is it just a typo? 这只是一个错字吗?
Paid_Amouint
vs. 与
Paid_Amount
Regards Ralph 问候拉尔夫
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