AJAX状态200在json_encode的PHP回显上引发错误

Question

Everything works fine with following program, except AJAX error fires: 使用以下程序，一切正常，但会引发AJAX错误：

javascript: javascript：

var data = {
    email: 'me@gmail.com',
    password: 'secretword'
};

$.ajax({
    type: "POST",
    dataType: "application/json",
    url: "http://localhost/CFBserver/validateUser.php",
    data: data,
    success: function (response) {
        console.log(response.responseText);
    },
    error: function (response) {
        console.log(response.responseText);
    }
});

} }

php: 的PHP：

    <?php

    $conn = mysqli_connect('localhost', 'root', '', 'cfbdata');
    if (mysqli_connect_errno($conn)) {
        echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }
    $email = filter_input(INPUT_POST, 'email', FILTER_SANITIZE_STRING);
    $password = filter_input(INPUT_POST, 'password', FILTER_SANITIZE_STRING);

    $sql = "SELECT * FROM users WHERE email = '$email' AND password = '$password'";

    if (!mysqli_query($conn, $sql)) {
        die('Error: ' . mysqli_error($conn));
    }

    $result = mysqli_query($conn, $sql);
    $numrows = mysqli_num_rows($result);
    if ($numrows > 0) {
        $message = array('result' => 'found',
            'email' => $email,
            'password' => $password,
        );
    } else {
        $message = array('result' => 'Not found',
            'email' => $email,
            'password' => $password,
        );
    }
    header('Content-type: application/json');
    echo json_encode($message);

    mysqli_close($conn);
    ?>

This is what console displays: 这是控制台显示的内容：

<html>
    <head>
        <meta charset="UTF-8">
        <title></title>
    </head>
    <body>
        {"result":"found","email":"me@gmail.com","password":"secretword"}
    </body>
</html>

So php finds the record in the mysql database but on return to AJAX, error fires. 因此，php在mysql数据库中找到记录，但返回AJAX时，会引发错误。 Why is this? 为什么是这样？

Answer 1

Your AJAX is expecting a JSON response, but is getting HTML. 您的AJAX期待JSON响应，但获取HTML。 That's why the request returns status code 200 (= OK), but your JS won't work. 这就是为什么请求返回状态代码200（= OK），但是您的JS无法使用的原因。

PHP's json_encode doesn't add HTML by itself, so you're probably outputting to a template (or you've wrapped your PHP in HTML). PHP的json_encode本身不会添加HTML，因此您可能正在输出到模板（或者您已将PHP封装为HTML）。

As others have also mentioned, you're open to SQL injection . 正如其他人也提到的那样，您可以进行SQL注入。 There is also no way to be sure your error method is firing, since both your AJAX' error and success do the same thing. 也没有办法确保您的错误方法正在触发，因为您的AJAX error和success都做同样的事情。

AJAX状态200在json_encode的PHP回显上引发错误

问题描述

1 个解决方案

解决方案1
0 2016-12-05 02:12:22

AJAX状态200在json_encode的PHP回显上引发错误

问题描述

1 个解决方案

解决方案1 0 2016-12-05 02:12:22

解决方案1
0 2016-12-05 02:12:22