[英]How to use JS to target specific domain html <a> links with CSS classes?
I use online note taking editors to take notes. 我使用在线笔记编辑器进行笔记。 One of them I'm using is called dynalist.io.
我正在使用的其中一个名为dynalist.io。
I run stylebot (chrome plugin) to apply specific CSS sheets to those pages 我运行stylebot(chrome插件)将特定的CSS表单应用于这些页面
Normally when i put a URL link inside of my documents, I put two types: 通常,当我在文档中放入URL链接时,我会放入两种类型:
I'd like to apply CSS styles on those <a href>
tags seperately, however the program defaults the same class for all domain links so I cannot use CSS classes to achieve this 我想分别在这些
<a href>
标记上应用CSS样式,但是该程序默认为所有域链接使用相同的类,因此我无法使用CSS类来实现此目的
unless (to my knowledge) use javascript to target <a href>
and make seperate classes for different domain links. 除非(据我所知)使用javascript定位
<a href>
并为不同的域链接创建单独的类。 Then apply CSS rules 然后应用CSS规则
Reference image: 参考图片:
How would I go about doing this? 我将如何去做呢?
edit: would I have to use greasemonkey to inject javascript? 编辑:我将不得不使用滑脂注入JavaScript吗?
You can add the following rules at your css file (this is not efficient): 您可以在css文件中添加以下规则(效率不高):
a[href^="http://i.imgur.com"] {
color: red !important;
}
It is like a regexp, and it is not efficient for a standard css, but in your case... will be good. 这就像一个正则表达式,对于标准的CSS来说效率不高,但是对于您来说……会很好。
EDIT: The !important
is just to make sure you will overwrite other css rules. 编辑:
!important
只是为了确保您将覆盖其他CSS规则。 The regexp is not efficient (for big pages) because the css need to check all the <a>
tag and make a control. 正则表达式效率不高(对于大页面),因为CSS需要检查所有
<a>
标记并进行控制。
If you need to change the color of other links, you need to create the same rule but with another link. 如果需要更改其他链接的颜色,则需要创建相同的规则,但要使用另一个链接。
If I understood you correctly, you want to select all links who are from imgur and add a class to them. 如果我对您的理解正确,则希望选择imgur中的所有链接,并向其中添加一个类。
You could do it like this: 您可以这样做:
Select all the a elements whose href attributes contains imgur . 选择所有其href属性包含imgur的a元素。
var elements = document.querySelectorAll('a[href*="imgur"]');
Add the class 'sup' to them: 向他们添加类“ sup”:
for (var i = 0, len = elements.length; i < len; i++) {
elements[i].classList.add('sup');
}
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