如何将多个值插入到具有不同行的一列上？

Question

I'm trying to store the question text and answer into different table. First I can stored the question text value, but subsequently when I insert the value for answer, it display

Fatal error: Uncaught exception 'PDOException' with message
'SQLSTATE[21S01]: Insert value list does not match column list: 1136 Column count doesn't match value count at row 1'

My objective is to store the question text on question table and answer in option table. I have tried a few method, but still can't get it to work. Those commented line are some of my methods.

HTML code:

<div class="container">
  <button type="button" class="btn btn-success" onclick="goBack()">
    <span class="glyphicon glyphicon-arrow-left"></span> Back
  </button><br><br>
  <p></p>
  <form class="table" method="post" id="mcq-form">
    <table class="table">

      <tbody>
        <tr>
          <td>Question:</td>
          <td><input type="text" size="80" name="questiontext"></td>
        </tr>
        <tr>
          <td>1. </td>
          <td><input type="text" size="70" name="ans1"><input value="1" name="ans" type="radio"></td>
        </tr>
        <tr>
          <td>2. </td>
          <td><input type="text" size="70" name="ans2"><input value="2" name="ans" type="radio"></td>
        </tr>
        <tr>
          <td>3. </td>
          <td><input type="text" size="70" name="ans3"><input value="3" name="ans" type="radio"></td>
        </tr>
        <tr>
          <td>4. </td>
          <td><input type="text" size="70" name="ans4"><input value="4" name="ans" type="radio"></td>
        </tr>
        <tr>
          <td align="center"><input type="submit" name="submit" value="Create"></td>
        </tr>
      </tbody>

    </table></form>
</div>

PHP code:

<?php

require_once 'dbConn.php';

if(!empty($_POST{'submit'})) {

    //$questiontext = $_POST['questiontext'];
    $anstext1 = $_POST['ans1'];
    $anstext2 = $_POST['ans2'];
    $anstext3 = $_POST['ans3'];
    $anstext4 = $_POST['ans4'];
    //$radiobtn = $_POST['ans'];

    //add the first record into question table
    /*$stmt1 = $conn->prepare("INSERT INTO `question`(question_text) VALUES(:questiontext)");
    $stmt1->bindParam(":questiontext",$questiontext);
    $stmt1->execute();*/

    //$answerArray = array["$anstext1", "$anstext2", "$anstext3", "$anstext4"];
    /*$value = array(':ans1', 'ans2', ':ans3', 'ans4');
    for($i=0; $i<=count($value); $i++) {
        $i = $value[$i];
    }*/

    $stmt2 = $conn->prepare("INSERT INTO `option_tbl`(option_answer) VALUES(':ans1', ':ans2', 'ans3', 'ans4')");

    $stmt2->bindParam(":ans1",$anstext1);
    $stmt2->bindParam(":ans2",$anstext2);
    $stmt2->bindParam(":ans3",$anstext3);
    $stmt2->bindParam(":ans4",$anstext4);
    $stmt2->execute();
    //$stmt2->execute();

    /*$conn->beginTransaction();

    //insert first query to question table
    $questionsql = ("INSERT INTO `question`(question_text) VALUES(:questiontext)");
    $q = $conn->prepare($questionsql);
    $q->bindValue(":questiontext",$questiontext);
    $q->execute();

    //insert second query to option table
    $answersql = ("INSERT INTO `option_tbl`(option_answer) VALUES(:ans1, :ans2, :ans3,:ans4)") ;
    $a = $conn->prepare($answersql);
    $a->bindValue("anstext1",$anstext1);
    $a->bindValue("anstext2",$anstext2);
    $a->bindValue("anstext3",$anstext3);
    $a->bindValue("anstext4",$anstext4);
    $a->execute();
    $conn->commit();*/

}
?>

Answer 1

First of all , you do not store multiple values in one column. You store them in multple rows. The error you have comes directly from this

$stmt2 = $conn->prepare("INSERT INTO `option_tbl`(option_answer) VALUES(':ans1', ':ans2', 'ans3', 'ans4')");

You are telling sql that you want to store something in the option_answer column but you are sending 4 different values.

it should look something like this:

$stmt2 = $conn->prepare("INSERT INTO `option_tbl`(option_answer) VALUES(:ans)");

Then

$stmt2->bindParam(":ans",$anstext1);
$stmt2->execute()
...
$stmt2->bindParam(":ans",$anstext4);
$stmt2->execute()

This still doesn't get you out of the woods. How do you know which question this answer relates to? YOu probably want something like

$stmt2 = $conn->prepare("INSERT INTO `option_tbl`(question, option_answer) VALUES(':question, :ans')");

Answer 2

@e4c5 explained it well enough why this is not working....

Try it like (You may also want to store question id else this will be of no use...Assuming you can edit it yourself according to your need...)

<?php

require_once 'dbConn.php';

if(!empty($_POST{'submit'})) {

    //$questiontext = $_POST['questiontext'];
    $answers[] = $_POST['ans1'];
    $answers[] = $_POST['ans2'];
     $answers[] = $_POST['ans3'];
     $answers[] = $_POST['ans4'];
    //$radiobtn = $_POST['ans'];

    //add the first record into question table
    /*$stmt1 = $conn->prepare("INSERT INTO `question`(question_text) VALUES(:questiontext)");
    $stmt1->bindParam(":questiontext",$questiontext);
    $stmt1->execute();*/

    //$answerArray = array["$anstext1", "$anstext2", "$anstext3", "$anstext4"];
    /*$value = array(':ans1', 'ans2', ':ans3', 'ans4');
    for($i=0; $i<=count($value); $i++) {
        $i = $value[$i];
    }*/
foreach( $answers as $answer){
    $stmt2 = $conn->prepare("INSERT INTO `option_tbl`(option_answer) VALUES(':ans')");

    $stmt2->bindParam(":ans",$answer);
    $stmt2->execute();
    //$stmt2->execute();
}
    /*$conn->beginTransaction();

    //insert first query to question table
    $questionsql = ("INSERT INTO `question`(question_text) VALUES(:questiontext)");
    $q = $conn->prepare($questionsql);
    $q->bindValue(":questiontext",$questiontext);
    $q->execute();

    //insert second query to option table
    $answersql = ("INSERT INTO `option_tbl`(option_answer) VALUES(:ans1, :ans2, :ans3,:ans4)") ;
    $a = $conn->prepare($answersql);
    $a->bindValue("anstext1",$anstext1);
    $a->bindValue("anstext2",$anstext2);
    $a->bindValue("anstext3",$anstext3);
    $a->bindValue("anstext4",$anstext4);
    $a->execute();
    $conn->commit();*/

}
?>