Laravel 5.3中的Symfony \\ Component \\ HttpKernel \\ Exception \\ NotFoundHttpException

Question

Previously I had trouble with route precedence with helps and suggestions I overcame it by adding regex in my route. Now my route is this:

Route::get('/{country}/{category}', ['as' => 'tour.list', 'uses' => 'LinkController@tourlist'])
            ->where('country', '[A-Za-z]+')->where('category', '[A-Za-z]+');

Route::get('/{category}/{slug}',['as' => 'single.tour', 'uses' => 'LinkController@singleTour'])
            ->where('category', '[A-Za-z]+')->where('category', '[w\d\-\_]+');

with this route I get error an error of:

Symfony \ Component \ HttpKernel \ Exception \ NotFoundHttpException

When I remove regex from first route I'm getting same problem as before and when I remove regex from 2nd route I get an error of:

Trying to get property of non-object 
(View: F:\project\resources\views\public\tours\show.blade.php) 

My methods in LinkController are:

public function tourlist($country, $category){
$tour = Tour::whereHas('category', function($q) use($category) {
            $q->where('name','=', $category);
        })
        ->whereHas('country', function($r) use($country) {
            $r->where('name','=', $country);
        })
        ->get();
    return view('public.tours.list')->withTours($tour);
}

public function singleTour($slug,$category)
{
$tour = Tour::where('slug','=', $slug)
              ->whereHas('category', function($r) use($category) {
            $r->where('name','=', $category);
        })
        ->first();
   return view('public.tours.show')->withTour($tour);
}

And my code in view is:

<a href="{{ route('single.tour',['category' => $tour->category->name, 'slug' => $tour->slug]) }}">{{$tour->title}}</a>

Answer 1

Change you Regex

where('category', '[w\\d\\-\\_]+'); to where('slug', '[A-Za-z\\d\\-\\_]+');

The above would solve the initial problem of the route not working properly.